按大多数匹配选择并订购

Question

假设我爆炸了搜索中传递的字符串.例如:"如果有狗" "如果有狗"(傻美国人).

我们根据""结果爆炸......

if
there
were
a
dog

现在我想跑一个 SQL select * from table_name query where column_name like '%something%' or column_name like '%somethingelse%'...

我正在尝试确定如何搜索表并按包含最多匹配的行进行排序.(即,如果第45行包含上述分割项中的4个而第21行仅包含2,则第45行应显示在结果的顶部).

这将是一种原始的"搜索相关性"逻辑.在SQL中有这种检索的特定术语吗？

建议？

Answer 1

只需将比较放在order by子句中,使用case语句将它们转换为0/1,然后将它们添加起来:

select *
from table_name query
where column_name like '%something%' or column_name like '%somethingelse%'
order by ((case when column_name like '%something%' then 1 else 0 end) +
          (case when column_name like '%somethingelse%' then 1 else 0 end)
          . . .
         ) desc

我倾向于将查询写成:

select (Match1+Match2+. . .) as NumMatches, <rest of columns>
from (select t.*,
             (case when column_name like '%something%' then 1 else 0 end) as Match1,
             . . .
      from tablename
     ) t
order by NumMatches desc