如何将参数传递给.Net中的Thread

Question

我有这样的功能:

public void view(string msg)
{
  messagebox.show(msg);
}
.

.

我想从一个线程向它传递参数..我正在使用.Net 1.1.我怎样才能做到这一点？

Answer 1

对于.NET 1.1,没有直接的方法,但是使用具有方法和状态的对象,在此示例中(从MSDN示例修改),ThreadState类被实例化并传递所需的状态,然后调用其方法并且使用传递状态.

public class ThreadState {
    private string msg;

    // The constructor obtains the state information.
    public ThreadState(string msg) {
        this.msg = msg;
    }

    public void view() {
        //Do something with msg
    }
}

public class Example {
    public static void Main() {
        ThreadState ts = new ThreadState("Hello World!");
        // Create a thread to execute the task, and then
        // start the thread.
        Thread t = new Thread(new ThreadStart(ts.view));
        t.Start();
        t.Join();
    }
}

对于.NET> 1.1(原始问题没有状态版本.)

您在Start方法中传递参数.您将收到一个需要回放到正确类型的对象.

Thread t = new Thread(view);
t.Start("Hello");

public void view(object msg) 
{
     string m = (string)msg;
     //Use msg
}

要么是这样,要么使用ParameterizedThreadStart委托.