Android系统.从拨号器启动应用程序

Question

这是我到目前为止,但是当我在拨号器中输入这个组合时没有任何反应

public class DialReceiver extends BroadcastReceiver
{
    @Override
  public void onReceive(Context context, final Intent intent) {

    if (intent.getAction().equals(android.content.Intent.ACTION_NEW_OUTGOING_CALL)) {
        String phoneNumber = intent.getExtras().getString( android.content.Intent.EXTRA_PHONE_NUMBER );

        if(phoneNumber.equals("*#588637#")) { 
            Intent intent1 = new Intent(context , Activity.class);
            intent1.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK );
            context.startActivity(intent1);
        }

    }

}
}

并在androidmanifest

    <receiver
        android:name=".receiver.DialReceiver"
        android:exported="true"
        android:process=":background"
        tools:ignore="ExportedReceiver" >
        <intent-filter>
            <action android:name="android.intent.action.NEW_OUTGOING_CALL" />
            <category android:name="android.intent.category.DEFAULT" />
        </intent-filter>
    </receiver>

Answer 1

尝试这些小改动..

String phoneNumber = intent.getExtras.getString("Intent.EXTRA_PHONE_NUMBER");

             if(phoneNumber.equals("*#588637#")) { 
             //do your stuff
             }

并且不要忘记在Manifest.xml文件中添加此行

<uses-permission android:name="android.permission.PROCESS_OUTGOING_CALLS"/>

你也可以找到这些有用的..

• http://android.programmerguru.com/simple-dialer-application/
• http://tikuflower.blogspot.com/2011/12/android.html