如何从POP3电子邮件中提取数据？

Question

我使用PHP从POP3服务器接收电子邮件.我有一个包含标题和正文的原始字符串.如何以类或数组的形式解析标题和正文？

我的例子:

Return-path: Envelope-to: x@x.de Delivery-date:
Wed, 06 Feb 2013 09:35:37 +0100 Received: from mail by
host6.toxpress.com with spam-scanned (Exim 4.80.1) (envelope-from ) id
1U30Tc-0003sH-LQ for x@x.de; Wed, 06 Feb 2013
09:35:36 +0100 X-Spam-Checker-Version: SpamAssassin 3.3.2 (2011-06-06)
on host6.toxpress.com X-Spam-Level: X-Spam-Status: No, score=-1.9
required=5.0 tests=BAYES_00,FREEMAIL_FROM,
RCVD_IN_DNSWL_NONE,TVD_SPACE_RATIO autolearn=ham version=3.3.2
Received: from moh3-ve2.go2.pl ([193.17.41.86] helo=moh3-ve1.go2.pl)
by host6.toxpress.com with esmtp (Exim 4.80.1) (envelope-from ) id
1U30Tc-0003rk-2b for x@x.de; Wed, 06 Feb 2013
09:35:32 +0100 Received: from moh3-ve1.go2.pl (unknown [10.0.0.157])
by moh3-ve1.go2.pl (Postfix) with ESMTP id BC734AF611B for ; Wed, 6
Feb 2013 09:34:31 +0100 (CET) Received: from unknown (unknown
[10.0.0.108]) by moh3-ve1.go2.pl (Postfix) with SMTP for ; Wed, 6 Feb
2013 09:34:31 +0100 (CET) Received: from
43.dynamic.chello.pl [89.69.42.127] by poczta.o2.pl with
ESMTP id jtIGfv; Wed, 06 Feb 2013 09:34:31 +0100 Message-ID:
<51121593.3090008@o2.pl> Date: Wed, 06 Feb 2013 09:34:27 +0100 From:
Tomasz Reply-To: tomasz_smykrowski@o2.pl Organization: Tomasz
User-Agent: Mozilla/5.0 (Windows NT 6.1; rv:20.0) Gecko/20100101
Thunderbird/20.0a2 MIME-Version: 1.0 To: x@x.de
Subject: adaads Content-Type: text/plain; charset=ISO-8859-1;
format=flowed Content-Transfer-Encoding: 7bit X-O2-Trust: 2, 64
X-O2-SPF: neutral dsadasdsaas .

而我希望能够做到的:

echo $from;
echo $replyTo;
echo $date;
echo $body;
echo $subject;
echo $charset;

Answer 1

看一下MIME电子邮件消息解析器类.
根据作者的描述:

此类可用于解析和解码MIME电子邮件.它支持解码单个RFC 2822 MIME消息或以mbox格式聚合多个消息的存档.解码的消息数据作为数组返回,该数组描述在消息文件或数据串中找到的一个或多个消息.多部分消息的主体可以被解码成不同的子消息.消息正文数据可以解码并保存到单独的文件中,因此该类可以处理大于可用内存的消息.