1 sql sql-server sql-server-2005 row-number
我正在尝试理解在我的查询中最外层选择上使用DISITINCT时使用row_number()函数以降序排序结果时看到的异常行为,如下所示:
SELECT DISTINCT (ID), State_Id, Name_Of_Trip, Date_Of_Travel, Creation_Date, Locking_Id, Applicant_Name, Reference_Number, State_Name
FROM (
SELECT app.ID, app.State_Id, app.Name_Of_Trip, app.Date_Of_Travel, app.Creation_Date, app.Locking_Id, app.Applicant_Name, app.Reference_Number,
State.Name AS State_Name, ROW_NUMBER() OVER(ORDER BY Reference_Number DESC) as rowNum
FROM Application_Leg AS app
INNER JOIN State AS state
ON app.State_Id = state.ID
WHERE (app.State_Id = 5 OR app.State_Id = 6 OR app.State_Id = 8) AND app.Organisation_Id=12
AND Leg_Number IN
(SELECT DISTINCT Leg_Number
from Application_Leg as al
INNER JOIN
Organisation as org
ON al.Organisation_Id = org.ID
WHERE al.ID=app.ID AND org.Approval_Required=1 AND Mode_Of_Transport=1))
as pagedApplications
WHERE rowNum BETWEEN 0 AND (0 + 10)
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当取出最外面的DISTINCT时,降序很好但是当它被包括时,结果不会以降序显示.
ORDER BYin ROW_NUMBER子句不保证结果集的顺序.
ROW_NUMBER 通常在查询计划中使用排序,这导致值排序出来.
这是副作用,不应该依赖.
DISTINCTHash Match (Aggregate)打破排序的用途.
添加ORDER BY子句到查询结尾:
SELECT DISTINCT (ID), State_Id, Name_Of_Trip, Date_Of_Travel, Creation_Date, Locking_Id, Applicant_Name, Reference_Number, State_Name
FROM (
SELECT app.ID, app.State_Id, app.Name_Of_Trip, app.Date_Of_Travel,
app.Creation_Date, app.Locking_Id, app.Applicant_Name, app.Reference_Number,
State.Name AS State_Name, ROW_NUMBER() OVER(ORDER BY Reference_Number DESC) as rowNum
FROM Application_Leg AS app
INNER JOIN
State AS state
ON app.State_Id = state.ID
WHERE app.State_Id IN (5, 6, 8)
AND app.Organisation_Id = 12
AND Leg_Number IN
(
SELECT Leg_Number
FROM Application_Leg as al
INNER JOIN
Organisation as org
ON al.Organisation_Id = org.ID
WHERE al.ID = app.ID
AND org.Approval_Required = 1
AND Mode_Of_Transport = 1
)
) AS pagedApplications
WHERE rowNum BETWEEN 0 AND (0 + 10)
ORDER BY
ReferenceNumber DESC
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还要注意它不会返回10不同的结果,它会返回DISTINCT第一个10结果.
如果你想要前者,请使用:
SELECT DISTINCT TOP 10 ID, State_Id, Name_Of_Trip, Date_Of_Travel, Creation_Date, Locking_Id, Applicant_Name, Reference_Number, State_Name
FROM (
SELECT app.ID, app.State_Id, app.Name_Of_Trip, app.Date_Of_Travel,
app.Creation_Date, app.Locking_Id, app.Applicant_Name, app.Reference_Number,
State.Name AS State_Name
FROM Application_Leg AS app
INNER JOIN
State AS state
ON app.State_Id = state.ID
WHERE app.State_Id IN (5, 6, 8)
AND app.Organisation_Id = 12
AND EXISTS
(
SELECT Leg_Number
FROM Application_Leg AS al
INNER JOIN
Organisation as org
ON al.Organisation_Id = org.ID
WHERE al.ID = app.ID
AND al.LegNumber = app.LegNumber
AND org.Approval_Required = 1
AND Mode_Of_Transport = 1
)
) AS pagedApplications
ORDER BY
ReferenceNumber DESC
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