严格标准:mysqli_next_result()错误与mysqli_multi_query

Question

我尝试过使用multi_query但是我一直在弹出严格的标准消息.

$querystring = "INSERT INTO responses VALUES('1', '2', '3', '4'); INSERT INTO responses VALUES('1', '2', '3', '4')";

if (mysqli_multi_query($db, $querystring)) {
   do {
       if ($result = mysqli_store_result($db)) {
           //
       }
   } while (mysqli_next_result($db));
}
echo "end";

我得到的错误信息是:

严格标准:mysqli_next_result():没有下一个结果集.请调用mysqli_more_results()/ mysqli :: more_results()来检查是否要调用此函数/方法

我试过添加和删除-;但没有运气.

Answer 1

虽然pipodesign纠正了$ querystring中的错误并缓解了问题,但没有提供有关严格标准错误的实际解决方案.

我不同意SirBT的建议,从DO WHILE更改为WHILE是没有必要的.

您收到的严格标准消息非常有用.要服从,请使用:

do{} while(mysqli_more_results($db) && mysqli_next_result($db));

然后,您无需在循环内部编写条件退出或中断,因为while条件将在第一次出现错误时中断循环.*注意,如果第一个查询有错误,do-while之前的if语句将拒绝进入循环.

在您的示例中,您只运行INSERT查询,因此您将不会收到任何要处理的结果集.如果要计算已添加的行数,请使用mysqli_affected_rows().

作为您问题的完整解决方案:

if(mysqli_multi_query($db,$querystring)){
    do{
        $cumulative_rows+=mysqli_affected_rows($db);
    } while(mysqli_more_results($db) && mysqli_next_result($db));
}
if($error_mess=mysqli_error($db)){echo "Error: $error_mess";}
echo "Cumulative Affected Rows: $cumulative_rows";

输出:

 // if no errors
Cumulative Affected Rows: 2

// if error on second query
Error: [something]
Cumulative Affected Rows: 1

// if error on first query
Error: [something]
Cumulative Affected Rows: 0

晚编辑:

由于mysqli的新手在这篇文章中遇到了绊脚石,我将提供一个通用但强大的代码片段,使用multi_query()处理带/不带结果集的查询,并添加一个功能来显示正在处理数组中的哪个查询...

经典"IF(){DO {} WHILE}"语法:

if(mysqli_multi_query($mysqli,implode(';',$queries))){
    do{
        echo "<br><br>",key($queries),": ",current($queries);  // display key:value @ pointer
        if($result=mysqli_store_result($mysqli)){   // if a result set
            while($rows=mysqli_fetch_assoc($result)){
                echo "<br>Col = {$rows["Col"]}";
            }
            mysqli_free_result($result);
        }
        echo "<br>Rows = ",mysqli_affected_rows($mysqli); // acts like num_rows on SELECTs
    } while(next($queries) && mysqli_more_results($mysqli) && mysqli_next_result($mysqli));
}
if($mysqli_error=mysqli_error($mysqli)){
    echo "<br><br>",key($queries),": ",current($queries),"Syntax Error:<br>$mysqli_error";  // display array pointer key:value
}
//if you want to use the snippet again...
$mysqli_error=null; // clear variables
reset($queries); // reset pointer

重新创建的轮子"WHILE {}"语法(...对于那些不喜欢测试后循环的人):

while((isset($multi_query) && (next($queries) && mysqli_more_results($mysqli) && mysqli_next_result($mysqli))) || (!isset($multi_query) && $multi_query=mysqli_multi_query($mysqli,implode(';',$queries)))){
    echo "<br><br>",key($queries),": ",current($queries);  // display array pointer key:value
    if($result=mysqli_store_result($mysqli)){
        while($rows=mysqli_fetch_assoc($result)){
            echo "<br>Col = {$rows["Col"]}";
        }
        mysqli_free_result($result);
    }
    echo "<br>Rows = ",mysqli_affected_rows($mysqli); // acts like num_rows on SELECTs
}
if($mysqli_error=mysqli_error($mysqli)){
    echo "<br><br>",key($queries),": ",current($queries),"Syntax Error:<br>$mysqli_error";  // display array pointer key:value
}
//if you want to use the snippet again...
$multi_query=$mysqli_error=null; // clear variables
reset($queries); // reset pointer

因此,给定以下查询的任一片段都将提供相同的输出:

查询数组:

$queries[]="SELECT * FROM `TEST`";
$queries[]="INSERT INTO `TEST` (Col) VALUES ('string1'),('string2')";
$queries[]="SELECT * FROM `TEST`";
$queries[]="DELETE FROM `TEST` WHERE Col LIKE 'string%'";

输出:

0: SELECT * FROM `TEST`
Rows = 0

1: INSERT INTO `TEST` (Col) VALUES ('string1'),('string2')
Rows = 2

2: SELECT * FROM `TEST`
Col = string1
Col = string2
Rows = 2

3: DELETE FROM `TEST` WHERE Col LIKE 'string%'
Rows = 2

根据您的需要修改我的代码段.如果您发现错误,请发表评论.