Ian*_*oyd 17 sql-server xpath sql-server-2005 sqlxml
我有一个包含XML列的表:
CREATE TABLE Batches(
BatchID int,
RawXml xml
)
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xml包含以下项目:
<GrobReportXmlFileXmlFile>
<GrobReport>
<ReportHeader>
<OrganizationReportReferenceIdentifier>1</OrganizationReportReferenceIdentifier>
<OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
</GrobReport>
<GrobReport>
<ReportHeader>
<OrganizationReportReferenceIdentifier>2</OrganizationReportReferenceIdentifier>
<OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
</GrobReport>
<GrobReport>
<ReportHeader>
<OrganizationReportReferenceIdentifier>3</OrganizationReportReferenceIdentifier>
<OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
</GrobReport>
<GrobReport>
<ReportHeader>
<OrganizationReportReferenceIdentifier>4</OrganizationReportReferenceIdentifier>
<OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
</GrobReport>
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我想要的是生成一个集合,其中包含:
OrganizationReportReferenceNumber OrganizationNumber
================================= ==================
1 4
2 4
3 4
4 4
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我试过了:
SELECT
foo.value('/ReportHeader/OrganizationReportReferenceIdentifier') AS ReportIdentifierNumber,
foo.value('/ReportHeader/OrganizationNumber') AS OrginazationNumber
FROM CDRBatches.RawXML.query('/GrobReportXmlFileXmlFile/GrobReport/ReportHeader') foo
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但这不起作用.我试过了:
SELECT
foo.value('/ReportHeader/OrganizationReportReferenceIdentifier') AS ReportIdentifierNumber,
foo.value('/ReportHeader/OrganizationNumber') AS OrginazationNumber
FROM RawXML.nodes('/GrobReportXmlFileXmlFile/GrobReport/ReportHeader') bar(foo)
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但这不起作用.所述的XPath表达式
/GrobReportXmlFileXmlFile/GrobReport/ReportHeader
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是正确的; 在任何其他xml系统中它返回:
<ReportHeader>
<OrganizationReportReferenceIdentifier>1</OrganizationReportReferenceIdentifier>
<OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
<OrganizationReportReferenceIdentifier>2</OrganizationReportReferenceIdentifier>
<OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
<OrganizationReportReferenceIdentifier>3</OrganizationReportReferenceIdentifier>
<OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
<ReportHeader>
<OrganizationReportReferenceIdentifier>4</OrganizationReportReferenceIdentifier>
<OrganizationNumber>4</OrganizationNumber>
</ReportHeader>
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所以,这是从我的疑问,我会很明显喜欢看到的.在阅读了十几个Stackover问题和答案之后,我就没有更接近解决问题了.
Bog*_*ean 30
SELECT b.BatchID,
x.XmlCol.value('(ReportHeader/OrganizationReportReferenceIdentifier)[1]','VARCHAR(100)') AS OrganizationReportReferenceIdentifier,
x.XmlCol.value('(ReportHeader/OrganizationNumber)[1]','VARCHAR(100)') AS OrganizationNumber
FROM Batches b
CROSS APPLY b.RawXml.nodes('/CasinoDisbursementReportXmlFile/CasinoDisbursementReport') x(XmlCol);
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演示:SQLFiddle
这有效,已经过测试...
SELECT n.c.value('OrganizationReportReferenceIdentifier[1]','varchar(128)') AS 'OrganizationReportReferenceNumber',
n.c.value('(OrganizationNumber)[1]','varchar(128)') AS 'OrganizationNumber'
FROM Batches t
Cross Apply RawXML.nodes('/GrobXmlFile/Grob/ReportHeader') n(c)
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