mysql匹配不返回不区分大小写的结果

Question

我有两张桌子:

CREATE TABLE IF NOT EXISTS `test1` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `bucket_id` int(10) unsigned NOT NULL COMMENT 'folder this component belongs to',
  `test1_name` varchar(81) NOT NULL COMMENT 'Name of this component',
  `test1_desc` varchar(1024) NOT NULL COMMENT 'Component Description',
  PRIMARY KEY (`id`),
  FULLTEXT KEY `test1_search` (`test1_name`,`test1_desc`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 ;

CREATE TABLE IF NOT EXISTS `bucket` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `bkt_name` varchar(81) NOT NULL COMMENT 'The name of this bucket',
  `bkt_desc` varchar(1024) NOT NULL COMMENT 'A description of this bucket',
  `bkt_keywords` varchar(512) DEFAULT NULL COMMENT 'keywords for searches',
  PRIMARY KEY (`id`),
  FULLTEXT KEY `fldr_search` (`bkt_desc`,`bkt_keywords`,`bkt_name`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=8 ;

Bucket只是一个持有者,而test1包含了所有可以进入存储桶的东西.例如:

INSERT INTO `bucket` (`id`, `bkt_name`, `bkt_desc`, `bkt_keywords`) VALUES
(1, 'Simpsons', 'The Simpsons Cartoon Family was first successful adult cartoon series', 'Homer, Marge, Lisa and Bart'),
(2, 'Griffins', 'The family from the popular family guy series', 'Peter, Lois, Meg, Chris, Stewie, Brian');

INSERT INTO `test1` (`id`, `bucket_id`, `bkt_name`, `bkt_desc`) VALUES
(1, 1, 'Homer Simpson', 'Homer the figurative head of the Simpsons Family and is the husband of Marge'),
(2, 2, 'Peter Griffin', 'Peter the figurative head of the Griffin family on the hit TV seriers The family Guy');

现在,使用以下查询,我想查找名称,描述或关键字包含搜索词"family"或其组件包含单词"family"的所有存储桶

到目前为止,我所拥有的是这个查询并且它没有返回混合大小写的结果,因为在"family"中找不到"Family".

SELECT *
FROM bucket
RIGHT JOIN test1 ON test1.bucket_id = bucket.id
WHERE
  bucket.isvisible > 0 AND
  MATCH(bucket.bkt_keywords, bucket.bkt_desc, bucket.bkt_name)
    AGAINST('family' IN BOOLEAN MODE) OR
  MATCH(test1.test1_name, test1.test1_desc) 
    AGAINST('family' IN BOOLEAN MODE)

我还应该补充说,所有文本字段都具有utf8_general_ci的排序规则,整个表格也是MyISAM.

Answer 1

我认为您的表格不用utf8_general_ci作整理，而是utf8_bin. 在修改表后，我能够重现您描述的行为，如下所示：

ALTER TABLE test1 CONVERT TO CHARACTER SET utf8 COLLATE utf8_bin;
ALTER TABLE bucket CONVERT TO CHARACTER SET utf8 COLLATE utf8_bin;

您也许应该将表的排序规则明确设置为：

ALTER TABLE test1 CONVERT TO CHARACTER SET utf8 COLLATE utf8_general_ci;
ALTER TABLE bucket CONVERT TO CHARACTER SET utf8 COLLATE utf8_general_ci;

如果以上更改了任何内容，我猜您的服务器或会话实际上已设置为默认情况下使用另一个排序规则（因为在您的表定义中未指定排序规则）。这可以通过以下方式检查：

SHOW GLOBAL VARIABLES LIKE 'collation_server';
SHOW SESSION VARIABLES LIKE 'collation_server';

Answer 2

答案显然是在两个 match against 子句周围添加一些括号。

SELECT *
FROM bucket
RIGHT JOIN test1 ON test1.bucket_id = bucket.id
WHERE bucket.isvisible > 0 AND
 ( MATCH(bucket.bkt_keywords, bucket.bkt_desc, bucket.bkt_name)
  AGAINST('family' IN BOOLEAN MODE) OR
  MATCH(test1.test1_name, test1.test1_desc) 
  AGAINST('family' IN BOOLEAN MODE) )