逐行分组

Question

我有一个文件,其行如下所示:

saldkfjaslk
    asdlkfja
    alsdkfjlk
aslkda;kdfsdlkfaj
sladkfjalskdfjlaskd
    sldkfaj
    lsadkfj
qwewrewst
se0polkjlkj
lpoerlwoej
    alskdjf
    asldkfjljlkjlk
sadlkfa

我想将以字符(不是空白)开头的行组合在一起,这些行以空格开头的连续行.我还想省略下一行不以空格开头的行.使用上面示例的所需输出如下所示:

[('saldkfjaslk', 'asdlkfja', 'alsdkfjlk'),
 ('sladkfjalskdfjlaskd', 'sldkfaj', 'lsadkfj'),
 ('lpoerlwoej', 'alskdjf', 'asldkfjljlkjlk')]

如何在Python中解析此文件？

Answer 1

>>> regex = re.compile(r"^\S.*(?:\n\s.*)+", re.MULTILINE)
>>> [tuple(match.split()) for match in regex.findall(s)]
[('saldkfjaslk', 'asdlkfja', 'alsdkfjlk'), 
 ('sladkfjalskdfjlaskd', 'sldkfaj', 'lsadkfj'), 
 ('lpoerlwoej', 'alskdjf', 'asldkfjljlkjlk')]

说明:

^    # Start of line
\S   # Match a non-whitespace character
.*   # Match the rest of the line
(?:  # Match...
 \n  #  a newline character
 \s  #  a whitespace character
 .*  #  and the rest of the line
)+   # once or more