在Android上格式化相对于现在的日期的最佳方式

Question

我正在Android应用中创建一个功能,以获取任意日期(过去,现在或将来)并找到相对于现在的差异.

我now和due变量都是longs,这是我的代码:

long now = System.currentTimeMillis();
long due = now + 864000;

Log.d("Time in 1 day", DateUtils.getRelativeTimeSpanString(due,now, DateUtils.DAY_IN_MILLIS));

我所要的输出是这样的yesterday,today,in 4 days或19/12/2012.但是,当前的输出返回in 0 days...

我不希望时间出现在这些日期字符串上.

我做错了什么,是在Android上格式化日期的最佳方法？

Answer 1

我想到的是改变:

DateUtils.getRelativeTimeSpanString(due, now, 0L, DateUtils.FORMAT_ABBREV_ALL);

由于文档说它返回相对于现在的时间.

如果失败则使用一些出色的库:

乔达时间

PrettyTime

过去

Answer 2

最后我实现了你想要的......

首先,您需要从这里下载Joda Time

将其解压缩到任何文件夹,并将joda-time-2.2.jar放入androidProject/libs文件夹.

主要活动

import org.joda.time.DateTime;
import org.joda.time.Days;
import org.joda.time.Months;
import org.joda.time.MutableDateTime;
import org.joda.time.Weeks;
import android.os.Bundle;
import android.app.Activity;
import android.util.Log;


public class MainActivity extends Activity
{
  private int day ;
  private int month ;
  private int year ;
  private int hour ;
  private int minute ;
  private long selectedTimeInMillis;
  private long currentTimeInMillis;
  private String strDay ="";

 @Override
 protected void onCreate(Bundle savedInstanceState) 
 {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    year = 2013;
    month = 8;
    day = 10;
    hour = 15;
    minute = 28;

    DateTime selectedTime = new DateTime(year,month,day,hour,minute);
    selectedTimeInMillis = selectedTime.getMillis();

    MutableDateTime epoch = new MutableDateTime();
    epoch.setDate(selectedTimeInMillis); //Set to Epoch time

    DateTime now = new DateTime();

    currentTimeInMillis = now.getMillis();

    int days = Days.daysBetween(epoch, now).getDays();
    int weeks = Weeks.weeksBetween(epoch, now).getWeeks();
    int months = Months.monthsBetween(epoch, now).getMonths();

    Log.v("days since epoch: ",""+days);
    Log.v("weeks since epoch: ",""+weeks);
    Log.v("months since epoch: ",""+months);


    if(selectedTimeInMillis < currentTimeInMillis) //Past 
    {       
        long yesterdayTimeInMillis = currentTimeInMillis - 86400000;

        DateTime today = new DateTime(currentTimeInMillis);
        int year = today.getDayOfYear();
        int intToday = today.getDayOfMonth();
        DateTime yesterday = new DateTime(yesterdayTimeInMillis);
        int intYesterday = yesterday.getDayOfMonth();
        DateTime selectedDay = new DateTime(selectedTimeInMillis);
        int intselectedDay = selectedDay.getDayOfMonth();
        int intselectedYear = selectedDay.getDayOfYear();

        if(intToday == intselectedDay & year == intselectedYear)
        {
            strDay = "today";
        }
        else if(intYesterday == intselectedDay)
        {
            strDay = "yesterday";
        }
        else
        {
            strDay = "before "+ days +" days from today";
        }


    }
    else if(selectedTimeInMillis > currentTimeInMillis) //Future
    {
        long tomorrowTimeInMillis = currentTimeInMillis + 86400000;

        DateTime tomorrow = new DateTime(tomorrowTimeInMillis);
        int intTomorrow = tomorrow.getDayOfMonth();
        DateTime today = new DateTime(selectedTimeInMillis);
        int intToday = today.getDayOfMonth();

        if(intToday == intTomorrow)
        {
            strDay = "tomorrow";
        }
        else
        {
            days = -days;
            strDay = "after "+ days +" days from today";
        }


    }

    Log.v("strDay: ",""+strDay);
  }
}

你只需要改变一天的值,你就会得到欲望的输出.目前我已将日期10作为输入,因此输出将是今天.

我设置日期/日= 10,月= 8,年= 2013,小时= 15,分钟= 28

对于过去的日期:

input day 9 output yesterday

input day 3 output before 7 days from today

input year 2012 and day 10 output before 365 days from today

对于未来日期:

input day 11 output tomorrow

input day 27 output after 17 days from today

input day 23 and year 2016 output after 1109 days from today

Answer 3

因此，您的计算基于毫秒单位，然后使用 SimpleDateFormat 格式化结果。

为此，您可以轻松使用 SimpleDateFormat 格式化程序，如下所示：

Date date = new Date(milliseconds);
SimpleDateFormat formatter = new SimpleDateFormat("EEEE dd MMMM yyyy");
String strDate = formatter.format(date);

因此，您的计算应该基于毫秒单位，然后使用 SimpleDateFormat 格式化结果。

该模式（“EEEE dd MMMM yyyy”）允许您获取日期格式，例如 Monday, 04 February 2013。

您可以根据需要更改模式：“EEEE dd/MM/yy”，...