Amm*_*eux 2 delphi ms-access delphi-xe3
我正在将一些信息存储到我的Access数据库中,一个参数是一个BLOB字段,在这种情况下是一个图像,加载到Timage中.
我正在使用此代码来保存它:
var
AStream : TMemoryStream;
begin
AStream := TMemoryStream.Create;
try
Image1.Picture.Graphic.SaveToStream(AStream);
AStream.Position := 0;
if Adotable1.Active then
begin
Adotable1.Edit;
TBlobField(Adotable1.FieldByName('Termograma')).LoadFromStream(AStream);
Adotable1.Post;
end;
finally
AStream.Free;
adotable1.Append;
adotable1['Data']:= datetimepicker1.Date;
adotable1['Temax']:= edit4.Text;
adotable1['Temin']:= edit5.Text;
adotable1['Descrição da Posição']:= memo1.Text;
adotable1['Comentários']:= memo2.Text;
adotable1.Post;
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但是我也通过点击"附加"部分中的相同按钮来存储其他信息.
当我按下保存按钮时,该信息不会存储在数据库中的相同ID中.
我该如何解决这个问题?
您正在编辑当前记录,将图像保存到该记录,附加新记录,并将其余信息保存到该新记录中.我想你打算添加一个完整的新记录,将图像和数据添加到新记录,然后保存这些更改.
试试这个:
var
AStream : TMemoryStream;
begin
if not AdoTable1.Active then
AdoTable1.Open;
Adotable1.Append;
AStream := TMemoryStream.Create;
try
Image1.Picture.Graphic.SaveToStream(AStream);
AStream.Position := 0;
TBlobField(Adotable1.FieldByName('Termograma')).LoadFromStream(AStream);
finally
AStream.Free;
end;
adotable1['Data']:= datetimepicker1.Date;
adotable1['Temax']:= edit4.Text;
adotable1['Temin']:= edit5.Text;
adotable1['Descrição da Posição']:= memo1.Text;
adotable1['Comentários']:= memo2.Text;
adotable1.Post;
end;
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