是)我有的:
表格1
????????????????????
? ID ? NAME ? AGE ?
????????????????????
? 0 ? John ? 15 ?
? 1 ? Chris ? 20 ?
????????????????????
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表2
?????????????????????????????????
? ID ? OCCUPATION ? ADDRESS ?
?????????????????????????????????
? 0 ? Bus Driver ? None ?
? 1 ? Lawyer ? some adress ?
?????????????????????????????????
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期望的输出:
表3
???????????????????????????????????????????????
? ID ? NAME ? AGE ? OCCUPATION ? ADDRESS ?
???????????????????????????????????????????????
? 0 ? John ? 15 ? Bus Driver ? None ?
? 1 ? Chris ? 20 ? Lawyer ? some adress ?
???????????????????????????????????????????????
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虽然我可以使用PHP mysql_query("SELECT .. "); mysql_query("INSERT ..");-ish方式完成此任务,但我想使用纯SQL来完成此任务.
JOIN 两个表:
SELECT
t1.ID,
t1.Name,
t1.Age,
t2.Occupation,
t2.Address
FROM table1 t1
INNER JOIN table2 t2 ON t1.ID = t2.ID;
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这会给你:
| ID | NAME | AGE | OCCUPATION | ADDRESS |
-----------------------------------------------
| 0 | John | 15 | Bus Driver | None |
| 1 | Chris | 20 | Lawyer | some adress |
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如果要table3直接从此选择创建新表,请执行以下操作:
CREATE Table Table3
AS
SELECT
t1.Name,
t1.Age,
t2.Occupation,
t2.Address
FROM table1 t1
INNER JOIN table2 t2 ON t1.ID = t2.ID;
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