如何使用ggplot2将光栅文件绘制为直方图？

Question

我有一个光栅文件,我想绘制为直方图,我使用hist()进行绘制,如下所示.但我想使用ggplot2进行绘图,以更好的方式绘制它.

conne <- file("C:\\fined.bin","rb")
r = raster(y)
hist(r, breaks=30, main="SMD_2010",
        xlab="Pearson correlation", ylab="Frequency", xlim=c(-1,1))

我试过这个:

  qplot(rating, data=r, geom="histogram")

错误:

            ggplot2 doesn't know how to deal with data of class RasterLayer

我需要绘制类似的东西:

http://docs.ggplot2.org/0.9.3/geom_histogram-28.png

Answer 1

作为快速解决方案,您可以使用结果 hist

f <- hist(r, breaks=30)
dat <- data.frame(counts= f$counts,breaks = f$mids)
ggplot(dat, aes(x = breaks, y = counts)) + 
  geom_bar(stat = "identity",fill='blue',alpha = 0.8)+
  xlab("Pearson correlation")+ ylab("Frequency")+
  scale_x_continuous(breaks = seq(-1,1,0.25),  ## without this you will get the same scale
                   labels = seq(-1,1,0.25))    ## as hist (question picture)

PS:也许你需要scale_x_discrete用来获得更好的轴外观

编辑添加渐变填充

ggplot(dat, aes(x = breaks, y = counts, fill =counts)) + ## Note the new aes fill here
  geom_bar(stat = "identity",alpha = 0.8)+
  xlab("Pearson correlation")+ ylab("Frequency")+
  scale_x_continuous(breaks = seq(-1,1,0.25),
                   labels = seq(-1,1,0.25))+
  scale_fill_gradient(low="blue", high="red")            ## to play with colors limits