meu*_*erd 0 postgresql sqlalchemy
SELECT sector.sector, count(*)
FROM reports, organization, sector
WHERE reports.org_id = organization.id
AND organization.id = sector.org_id
GROUP BY sector.sector;
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老实说,我甚至不确定从哪里开始表达这个GROUP BY并加入sqlalchemy.
db.query(func.count(Sector.sector), Sector.sector).\
join(Organzation).join(Report).\
group_by(Sector.sector).all()
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我能够将其表示为以下表达式.我之前的努力失败了,因为我需要进行db.rollback()尴尬的失败尝试.
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