Cha*_*haz 58 django django-rest-framework
我想使用Django Rest Framework和一个API调用来保存和更新多个实例.例如,假设我有一个可以拥有多个"教师"的"课堂"模型.如果我想创建多个教师,然后更新他们所有的课堂号码,我该怎么做?我是否必须为每位老师拨打API电话?
我知道目前我们无法保存嵌套模型,但我想知道我们是否可以在教师级别保存它.谢谢!
Tom*_*eld 67
我知道这是前一段时间被问到的,但我发现它同时试图弄清楚这一点.
事实证明,如果many=True
在为模型实例化序列化程序类时传递,则它可以接受多个对象.
这是提到这里的Django的REST框架文件
对于我的情况,我的观点看起来像这样:
class ThingViewSet(viewsets.ModelViewSet):
"""This view provides list, detail, create, retrieve, update
and destroy actions for Things."""
model = Thing
serializer_class = ThingSerializer
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我真的不想写一大堆样板文件只是为了直接控制序列化程序的实例化并传递many=True
,所以在我的序列化程序类中我覆盖了__init__
:
class ThingSerializer(serializers.ModelSerializer):
def __init__(self, *args, **kwargs):
many = kwargs.pop('many', True)
super(ThingSerializer, self).__init__(many=many, *args, **kwargs)
class Meta:
model = Thing
fields = ('loads', 'of', 'fields', )
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将数据发布到此视图的列表URL,格式如下:
[
{'loads':'foo','of':'bar','fields':'buzz'},
{'loads':'fizz','of':'bazz','fields':'errrrm'}
]
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使用这些详细信息创建了两个资源.哪个好看.
Rog*_*ins 39
我得出了与Daniel Albarral类似的结论,但这里有一个更简洁的解决方案:
class CreateListModelMixin(object):
def get_serializer(self, *args, **kwargs):
""" if an array is passed, set serializer to many """
if isinstance(kwargs.get('data', {}), list):
kwargs['many'] = True
return super(CreateListModelMixin, self).get_serializer(*args, **kwargs)
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小智 16
这是另一种解决方案,您不需要覆盖序列化__init__
方法.只需覆盖您的视图(ModelViewSet)'create'
方法.注意事项many=isinstance(request.data,list)
.这里many=True
当您发送要创建的对象数组时,以及False
只发送一个对象时.这样,您可以保存项目和列表!
from rest_framework import status, viewsets
from rest_framework.response import Response
class ThingViewSet(viewsets.ModelViewSet):
"""This view snippet provides both list and item create functionality."""
#I took the liberty to change the model to queryset
queryset = Thing.objects.all()
serializer_class = ThingSerializer
def create(self, request, *args, **kwargs):
serializer = self.get_serializer(data=request.data, many=isinstance(request.data,list))
serializer.is_valid(raise_exception=True)
self.perform_create(serializer)
headers = self.get_success_headers(serializer.data)
return Response(serializer.data, status=status.HTTP_201_CREATED, headers=headers)
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aka*_*nom 11
我无法弄清楚将request.DATA从字典转换为数组 - 这限制了我对Tom Manterfield工作解决方案的能力.这是我的解决方案:
class ThingSerializer(serializers.ModelSerializer):
def __init__(self, *args, **kwargs):
many = kwargs.pop('many', True)
super(ThingSerializer, self).__init__(many=many, *args, **kwargs)
class Meta:
model = Thing
fields = ('loads', 'of', 'fields', )
class ThingViewSet(mixins.CreateModelMixin, viewsets.GenericViewSet ):
queryset = myModels\
.Thing\
.objects\
.all()
serializer_class = ThingSerializer
def create(self, request, *args, **kwargs):
self.user = request.user
listOfThings = request.DATA['things']
serializer = self.get_serializer(data=listOfThings, files=request.FILES, many=True)
if serializer.is_valid():
serializer.save()
headers = self.get_success_headers(serializer.data)
return Response(serializer.data, status=status.HTTP_201_CREATED,
headers=headers)
return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
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然后我在客户端运行相当于这个:
var things = {
"things":[
{'loads':'foo','of':'bar','fields':'buzz'},
{'loads':'fizz','of':'bazz','fields':'errrrm'}]
}
thingClientResource.post(things)
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我认为尊重该框架的最佳架构的最佳方法是创建一个如下所示的mixin:
class CreateListModelMixin(object):
def create(self, request, *args, **kwargs):
"""
Create a list of model instances if a list is provides or a
single model instance otherwise.
"""
data = request.data
if isinstance(data, list):
serializer = self.get_serializer(data=request.data, many=True)
else:
serializer = self.get_serializer(data=request.data)
serializer.is_valid(raise_exception=True)
self.perform_create(serializer)
headers = self.get_success_headers(serializer.data)
return Response(serializer.data, status=status.HTTP_201_CREATED,
headers=headers)
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然后,您可以像这样覆盖ModelViewSet的CreateModelMixin:
class <MyModel>ViewSet(CreateListModelMixin, viewsets.ModelViewSet):
...
...
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现在在客户端中,您可以像这样工作:
var things = [
{'loads':'foo','of':'bar','fields':'buzz'},
{'loads':'fizz','of':'bazz','fields':'errrrm'}
]
thingClientResource.post(things)
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要么
var thing = {
'loads':'foo','of':'bar','fields':'buzz'
}
thingClientResource.post(thing)
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编辑:
正如罗杰·柯林斯认为她的反应是更聪明的覆盖比“创造”的get_serializer方法。
你可以简单地覆盖get_serializer
法在APIView并传递many=True
到get_serializer
像这样的基础视角:
class SomeAPIView(CreateAPIView):
queryset = SomeModel.objects.all()
serializer_class = SomeSerializer
def get_serializer(self, instance=None, data=None, many=False, partial=False):
return super(SomeAPIView, self).get_serializer(instance=instance, data=data, many=True, partial=partial)
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我想出了一个简单的例子 post
序列化器.py
from rest_framework import serializers
from movie.models import Movie
class MovieSerializer(serializers.ModelSerializer):
class Meta:
model = Movie
fields = [
'popularity',
'director',
'genre',
'imdb_score',
'name',
]
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视图.py
from rest_framework.response import Response
from rest_framework import generics
from .serializers import MovieSerializer
from movie.models import Movie
from rest_framework import status
from rest_framework.permissions import IsAuthenticated
class MovieList(generics.ListCreateAPIView):
queryset = Movie.objects.all().order_by('-id')[:10]
serializer_class = MovieSerializer
permission_classes = (IsAuthenticated,)
def list(self, request):
queryset = self.get_queryset()
serializer = MovieSerializer(queryset, many=True)
return Response(serializer.data)
def post(self, request, format=None):
data = request.data
if isinstance(data, list): # <- is the main logic
serializer = self.get_serializer(data=request.data, many=True)
else:
serializer = self.get_serializer(data=request.data)
if serializer.is_valid():
serializer.save()
return Response(serializer.data, status=status.HTTP_201_CREATED)
return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
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这些行是多实例的实际逻辑 -
data = request.data
if isinstance(data, list): # <- is the main logic
serializer = self.get_serializer(data=request.data, many=True)
else:
serializer = self.get_serializer(data=request.data)
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当我们发送数据时,它会在里面list
有点像这样 -
[
{
"popularity": 84.0,
"director": "Stanley Kubrick",
"genre": [
1,
6,
10
],
"imdb_score": 8.4,
"name": "2001 : A Space Odyssey"
},
{
"popularity": 84.0,
"director": "Stanley Kubrick",
"genre": [
1,
6,
10
],
"imdb_score": 8.4,
"name": "2001 : A Space Odyssey"
}
]
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