mar*_*les 26 java string duplicates java.util.scanner
我得到以下代码:
int nnames;
String names[];
System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = in.nextInt();
names = new String[nnames];
for (int i = 0; i < names.length; i++){
System.out.print("Type a name: ");
names[i] = in.nextLine();
}
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该代码的输出如下:
How many names are you going to save:3
Type a name: Type a name: John Doe
Type a name: John Lennon
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注意它是如何跳过第一个名字的?它跳过它并直接进入第二个名称输入.我试过看是什么导致了这个,但我似乎无法指出它.我希望有一个人可以帮助我.谢谢
Jos*_*hua 26
出错的原因是nextInt只拉取整数,而不是换行符.如果在for循环之前添加in.nextLine(),它将占用空的新行并允许您输入3个名称.
int nnames;
String names[];
System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = in.nextInt();
names = new String[nnames];
in.nextLine();
for (int i = 0; i < names.length; i++){
System.out.print("Type a name: ");
names[i] = in.nextLine();
}
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或者只是读取该行并将该值解析为整数.
int nnames;
String names[];
System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = Integer.parseInt(in.nextLine().trim());
names = new String[nnames];
for (int i = 0; i < names.length; i++){
System.out.print("Type a name: ");
names[i] = in.nextLine();
}
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