jsonrpc4j:如何向参数添加类型信息？

Question

我正在使用jsonrpc4j并被卡住了.我举了一个例子来说明我的问题:

抽象类:

@JsonTypeInfo(use = JsonTypeInfo.Id.NAME)
@JsonSubTypes(value = { @JsonSubTypes.Type(value = Walnut.class) })
public abstract class Nut {

}

具体子类:

public class Walnut extends Nut {

}

服务接口:

public interface ServiceInterface {
    public Nut getNut();
    public void setNut(Nut nut);
}

服务本身:

public class Service implements ServiceInterface {
    public Nut getNut() { return new Walnut(); }
    public void setNut(Nut nut) {}
}

服务器:

JsonRpcServer rpcServer = new JsonRpcServer(new ObjectMapper(), new Service());
StreamServer streamServer = new StreamServer(rpcServer, 50, 1420,
        50, InetAddress.getByName("127.0.0.1"));
streamServer.start();

客户:

JsonRpcClient jsonRpcClient = new JsonRpcClient(new ObjectMapper());
ServiceInterface remoteService = ProxyUtil.createClientProxy(
        ServiceInterface.class.getClassLoader(),
        ServiceInterface.class, jsonRpcClient,
        new Socket(InetAddress.getByName("127.0.0.1"), 1420));

如果我调用remoteService.getNut(),一切都按预期工作,日志打印:

JSON-PRC Request: {"id":"6064348714687420633","jsonrpc":"2.0","method":"getNut"}
JSON-PRC Response: {"jsonrpc":"2.0","id":"6064348714687420633",
        "result":{"@type":"Walnut"}}

如果我调用remoteService.setNut(new Walnut())服务器抛出异常,则日志打印:

JSON-PRC Request {"id":"9194853851254039397","jsonrpc":"2.0",
        "method":"setNut","params":[{}]}
Error in JSON-RPC Service com.fasterxml.jackson.databind.JsonMappingException:
        Unexpected token (END_OBJECT), expected FIELD_NAME:
        missing property '@type' that is to contain type id  (for class Nut)

缺少参数的类型信息,因为代理将所有参数包装到一个对象数组中(请参阅我的上一个问题,以了解在这种情况下缺少信息类型的原因).

如何实现所需的序列化？我尝试启用默认类型并通过混合注释(使用@JsonTypeInfo)Object.class,但都失败了(下面的例外).

启用默认输入[ remoteService.getNut(),服务器端错误]:

Exception while handling request
        com.fasterxml.jackson.databind.JsonMappingException:
        Unexpected token (START_OBJECT), expected START_ARRAY:
        need JSON Array to contain As.WRAPPER_ARRAY type information for
        class com.fasterxml.jackson.databind.JsonNode

启用默认输入[ remoteService.setNut(new Walnut()),客户端错误]:

Exception in thread "main" java.lang.IllegalArgumentException:
        Unexpected token (START_ARRAY), expected VALUE_STRING:
        need JSON String that contains type id (for subtype of
        com.fasterxml.jackson.databind.JsonNode)

使用mix-in [ remoteService.getNut(),服务器端错误]:

Exception while handling request
        java.lang.IllegalArgumentException:
        Could not resolve type id 'DefaultErrorResolver$ErrorData'
        into a subtype of
        [simple type, class com.fasterxml.jackson.databind.JsonNode]

使用mix-in [ remoteService.setNut(new Walnut()),客户端错误]:

Exception in thread "main" java.lang.ClassCastException:
        [Ljava.lang.Object; cannot be cast to
        com.fasterxml.jackson.databind.JsonNode

有任何想法吗？

Answer 1

我通过修补库解决了我的问题.现在它逐个序列化所有参数,然后将它们连接起来.可以在http://code.google.com/p/jsonrpc4j/issues/detail?id=49找到错误报告和修补程序.