在每次迭代中分配"it"(groovy)

Question

嘿,我尝试修剪groovy列表中的每个字符串项

list.each() { it = it.trim(); }

但这仅适用于闭包,在列表中字符串仍然是"foo","bar"和"groovy".

我怎样才能实现这一目标？

Answer 1

list = list.collect { it.trim() }

Answer 2

您还可以使用spread运算符:

def list = [" foo", "bar ", " groovy "]
list = list*.trim()
assert "foo" == list[0]
assert "bar" == list[1]
assert "groovy" == list[2]