Ner*_*ero 4 c++ exc-bad-access mysql-connector
在Xcode中使用C++我尝试使用MySQL Connector/C++访问MySQL数据库.问题是该程序(使用Xcode编译)总是崩溃
EXC_BAD_ACCESS (code=13, address=0x0)
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在打电话时
driver->connect(url, user, pass)
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在Xcode中我创建了一个完整的新项目(OS X>命令行工具),在main.cpp中插入代码(见下文),添加了Boost和MySQL Connector头包含路径以及libmysqlcppconn.6.1.1.1.dylib作为Link库并点击"运行"按钮.
接下来的事情是,当我手动编译程序时
c++ -o test -I /usr/local/mysqlConnector/include/ -lmysqlcppconn main.cpp
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程序运行正常,并在表上运行INSERT语句.
程序代码取自MySQL Connector/C++示例,即pthreads.cpp示例,但截断为基本部分:
/* Standard C++ includes */
#include <stdlib.h>
#include <iostream>
#include <sstream>
#include <stdexcept>
#include <mysql_connection.h>
#include <mysql_driver.h>
#include <cppconn/driver.h>
#include <cppconn/exception.h>
#include <cppconn/resultset.h>
#include <cppconn/statement.h>
std::string url;
std::string user;
std::string pass;
std::string database;
/**
* Usage example for Driver, Connection, (simple) Statement, ResultSet
*/
int main(int argc, const char **argv)
{
sql::Driver *driver;
std::auto_ptr< sql::Connection > con;
url = "tcp://127.0.0.1:3306";
user = "appserver";
pass = "testpw";
database = "appserver";
try {
driver = sql::mysql::get_driver_instance();
/* Using the Driver to create a connection */
con.reset(driver->connect(url, user, pass));
con->setSchema(database);
sql::Statement* stmt = con->createStatement();
stmt->execute("INSERT INTO testtable (testnumber) values (5)");
} catch (sql::SQLException &e) {
return EXIT_FAILURE;
} catch (std::runtime_error &e) {
return EXIT_FAILURE;
}
return EXIT_SUCCESS;
}
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好的,问题解决了.
这里的问题是一个编译标志.MySQL Connector/C++是在没有
-stdlib=libc++标志的情况下编译的,但Xcode在其命令中添加了compile/link标志.这导致了崩溃.这也解释了为什么手动编译的程序工作,因为我没有在编译命令中包含该标志.
为了更清楚:我用-stdlib=libc++标志重新编译了MySQL Connector/C++ .那么Xcode编译的程序对我来说很好.为了编译我添加的MySQL Connector/C++
-DMYSQL_CXXFLAGS=-stdlib=libc++
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cmake安装连接器时需要运行的命令.
make VERBOSE=1
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然后证明在编译连接器源时实际使用了该标志.