错误:没有匹配函数来调用'min(long unsigned int&,unsigned int&)'

Question

我使用的是ubuntu 12.04 - 64位.我用boost 1.46,1.48,1.52和gcc 4.4和4.6测试它当我尝试编译时:

while (m_burstReqBeatsRemain) {
                if (m_burstReqAddress % m_dramRowSize == 0) {
                    m_admRequestQueue.push_back(adm_request());
                    adm_request &req = m_admRequestQueue.back();
                    req.address = m_burstReqAddress;
                    req.command = tlm::TLM_READ_COMMAND;
                    //call to min function
                    req.readLen = std::min(m_burstReqBeatsRemain * sizeof(Td), m_dramRowSize);
                }
                m_burstReqBeatsRemain--;
                m_burstReqAddress += sizeof(Td);
                m_ocpTxnQueue.push_back(m_ocpReq);
}

我收到此错误:

no matching function for call to ‘min(long unsigned int&, unsigned int&)
from /usr/include/c++/4.6/bits/stl_algobase.h*

注意:使用ubuntu 12.04 32位工作正常

知道如何解决这个问题吗？

Answer 1

std::min是一个函数模板,T其中是函数的两个 参数的类型.但是你似乎传递了不同类型的函数参数,并依赖于函数参数的模板参数推导,这是不可能的.

所以修复是:

• 要么不依赖模板参数推导,而是明确提到模板参数:

  std::min<unsigned long>(ulongarg, uintarg); //ok
       //^^^^^^^^^^^^^^^ 
       //don't rely on template argument deduction
       //instead pass template argument explicitly.
  

• 或传递相同类型的函数参数:

  std::min(ulongarg, static_cast<unsigned long>(uintarg)); //ok
                    //^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
                    //pass both arguments of same type