获取Scala中实例方法的函数值

Question

如何获取f实例方法的函数值？

class X(i : Int){
    def method(y : Int) = y + i
}

val x = new X(10)
val f : (Int) => Int = ?

val r = x.method(2)
val r2 = f(2)

调用x.method(2)和f(2)将是相同的方法调用.

Answer 1

scala> class X(i : Int){ def method(y : Int) = y + i }

defined class X

scala> val x = new X(10)

x: X = X@15b28d8

scala> val f = x.method _

f: (Int) => Int = <function>

scala> val r = x.method(2)

r: Int = 12

scala> val r2 = f(2)

r2: Int = 12