httplib.InvalidURL:非数字端口:

use*_*563 7 python file

我正在尝试编写一个脚本,检查是否存在多个网址:

import httplib

with open('urls.txt') as urls:
    for url in urls:
        connection = httplib.HTTPConnection(url)
        connection.request("GET")
        response = connection.getresponse()
        if response.status == 200:
            print '[{}]: '.format(url), "Up!"
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但我得到了这个错误:

Traceback (most recent call last):
  File "test.py", line 5, in <module>
    connection = httplib.HTTPConnection(url)
  File "/usr/lib/python2.7/httplib.py", line 693, in __init__
    self._set_hostport(host, port)
  File "/usr/lib/python2.7/httplib.py", line 721, in _set_hostport
    raise InvalidURL("nonnumeric port: '%s'" % host[i+1:])
httplib.InvalidURL: nonnumeric port: '//globo.com/galeria/amazonas/a.html
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怎么了?

Atu*_*ind 19

这可能是一个简单的解决方案

connection = httplib.HTTPConnection(url)
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你正在使用httpconnection所以没有必要给网址,http://iGyan.org,但你需要给iGyan.org.

简而言之http://,https://从URL中删除和,因为它httplib正在考虑:作为端口号,端口号必须是数字,

希望这可以帮助!


tom*_*tom 6

httplib.HttpConnectionhostport在其构造远程URL的,而不是整个URL.

对于您的用例,它更容易使用urllib2.urlopen.

import urllib2

with open('urls.txt') as urls:
    for url in urls:
        try:
            r = urllib2.urlopen(url)
        except urllib2.URLError as e:
            r = e
        if r.code in (200, 401):
            print '[{}]: '.format(url), "Up!"
        elif r.code == 404:
            print '[{}]: '.format(url), "Not Found!" 
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