excel电子邮件验证公式

Question

我有一个列,人们手动输入电子邮件地址.我想使用以下公式验证电子邮件地址:

=AND(FIND(“@”,A2),FIND(“.”,A2),ISERROR(FIND(” “,A2)))

但excel会出现错误,即您键入的公式包含错误.对我来说,公式看起来是对的.你们有什么建议吗？

Answer 1

我的代码出现了同样的错误,看起来你没有"普通"双引号,这与这个符号不同:".

试试我的拼写:=AND(FIND("@",A2),FIND(".",A2),ISERROR(FIND(" ",A2)))- 希望会有所帮助!

编辑:

另外,考虑使用=AND(NOT(ISERROR(FIND("@",A1))),NOT(ISERROR(FIND(".",A1))),ISERROR(FIND(" ",A1)))- 这将防止错误@或.丢失.尽管如此,这仍然可以通过aaa@.,但我认为即使是这种直截了当的方法也有权使用)

Answer 2

在excel中验证电子邮件的另一种方法是使用VBA代码:请参阅以下代码,该代码取自http://www.vbaexpress.com/kb/getarticle.php?kb_id=281,它的工作原理非常好,您可以修改基于代码的代码根据您的需求.

Sub email() 
Dim txtEmail As String 
txtEmail = InputBox("Type the address", "e-mail address") 

Dim Situacao As String 

 ' Check e-mail syntax
If IsEmailValid(txtEmail) Then 
    Situacao = "Valid e-mail syntax!" 
Else 
    Situacao = "Invalid e-mail syntax!" 
End If 
 ' Shows the result
MsgBox Situacao 
End Sub 
Function IsEmailValid(strEmail) 
Dim strArray As Variant 
Dim strItem As Variant 
Dim i As Long, c As String, blnIsItValid As Boolean 
blnIsItValid = True 

i = Len(strEmail) - Len(Application.Substitute(strEmail, "@", "")) 
If i <> 1 Then IsEmailValid = False: Exit Function 
ReDim strArray(1 To 2) 
strArray(1) = Left(strEmail, InStr(1, strEmail, "@", 1) - 1) 
strArray(2) = Application.Substitute(Right(strEmail, Len(strEmail) - Len(strArray(1))), "@", "") 
For Each strItem In strArray 
    If Len(strItem) <= 0 Then 
        blnIsItValid = False 
        IsEmailValid = blnIsItValid 
        Exit Function 
    End If 
    For i = 1 To Len(strItem) 
        c = LCase(Mid(strItem, i, 1)) 
        If InStr("abcdefghijklmnopqrstuvwxyz_-.", c) <= 0 And Not IsNumeric(c) Then 
            blnIsItValid = False 
            IsEmailValid = blnIsItValid 
            Exit Function 
        End If 
    Next i 
    If Left(strItem, 1) = "." Or Right(strItem, 1) = "." Then 
        blnIsItValid = False 
        IsEmailValid = blnIsItValid 
        Exit Function 
    End If 
Next strItem 
If InStr(strArray(2), ".") <= 0 Then 
    blnIsItValid = False 
    IsEmailValid = blnIsItValid 
    Exit Function 
End If 
i = Len(strArray(2)) - InStrRev(strArray(2), ".") 
If i <> 2 And i <> 3 Then 
    blnIsItValid = False 
    IsEmailValid = blnIsItValid 
    Exit Function 
End If 
If InStr(strEmail, "..") > 0 Then 
    blnIsItValid = False 
    IsEmailValid = blnIsItValid 
    Exit Function 
End If 
IsEmailValid = blnIsItValid 
End Function 

有关如何查看说明,请访问http://www.vbaexpress.com/kb/getarticle.php?kb_id=281#instr