玩家和怪物在我的游戏中一起错过

Question

在我的C#游戏TextQuest中,战斗系统正在进行中,我遇到了一个问题.如果玩家错过了Monster也错过了(总是在同一时间).这是使用过的代码:

private void button1_Click(object sender, EventArgs e)
    {
        Monster_Class mc = new Monster_Class();
        Account_Class ac = new Account_Class();
        if (hitOrMiss())
        {
            int hit = -1;
            hit = mc.hitAmount(ac.getAtk(Properties.Settings.Default.CurrentUser), mc.getDef(monster));
            mhealth -= hit;
            if (hit == -1)
            {
                setText("You missed.");
            }
            else
            {
                setText("You hit " + hit + ".");
            }
            monsterHit();
            update();
        }
        else
        {
            setText("You missed.");
            monsterHit();
        }
    }

private void monsterHit()
{
    Monster_Class mc = new Monster_Class();
    Account_Class ac = new Account_Class();
    if (hitOrMiss())
    {
        int hit = -1;
        hit = mc.hitAmount(mc.getAtk(monster), ac.getDef(Properties.Settings.Default.CurrentUser));
        phealth -= hit;
        if (hit == -1)
        {
            addText(monster + " missed.");
        }
        else
        {
            addText(monster + " hit " + hit + ".");
        }
    }
    else
    {
        addText(monster + " missed.");
    }
}

private bool hitOrMiss()
{
    bool hit = true;
    Random rand = new Random();
    if (rand.Next(101) < 15)
    {
        hit = false;
    }
    return hit;
}

public int hitAmount(int Atk, int Def)
{
    int hit = -1;
    Random rand = new Random();
    int deturm = rand.Next(6);
    try
    {
        hit = ((Atk + deturm * 3) / Def + 1) / 2;
        if (hit == 0)
        {
            hit = 1;
        }
    }
    catch { }
    return hit;
}

此外,如果您对损坏的数量有更好的想法,请告诉我.因为我只是把数字和符号放在一起

Answer 1

每次需要随机数时,您不希望创建新的Random对象.否则我怀疑你会得到相同的数字!定义一次全局Random对象,并在每个随机数请求中使用它.