Glib信号 - 如何检查实例的处理程序是否已被阻止?

GTK*_*boy 6 c gtk gobject glib

在阻止实例的处理程序之后g_signal_handler_block,是否可以检查处理程序是否仍然被阻塞或者同时被g_signal_handler_unblock解除阻塞,除了将状态存储在布尔变量中之外?

我希望这样的事情是可能的

g_signal_handler_block (selection, handler_id_row_selected);
if (g_signal_handler_is_blocked (selection, handler_id_row_selected))
  g_print ("is still blocked");
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但是一个"g_signal_handler_is_blocked"功能不存在.g_signal_handler_is_connected由于信号处理程序保持连接,因此函数返回TRUE,因此不是正确的函数.

我试过g_signal_handler_find (),因为有G_SIGNAL_MATCH_UNBLOCKED一种匹配类型,但它还没有工作.即使我已经重写了我的代码,我仍然想知道它是否可能,因为我相对经常使用阻塞/解除阻塞.

ntd*_*ntd 2

g_signal_handler_find这里正在按预期工作。这是我的测试用例:

#include <gtk/gtk.h>

gboolean
g_signal_handlers_is_blocked_by_func(gpointer instance, GFunc func, gpointer data)
{
    return g_signal_handler_find(instance,
                                 G_SIGNAL_MATCH_FUNC | G_SIGNAL_MATCH_DATA | G_SIGNAL_MATCH_UNBLOCKED,
                                 0, 0, NULL, func, data) == 0;
}

static void
handler(void)
{
    g_print("handler called\n");
}

static void
switch_blocking(GtkWidget *button)
{
    GFunc func = (GFunc) handler;

    if (g_signal_handlers_is_blocked_by_func(button, func, NULL)) {
        g_signal_handlers_unblock_by_func(button, func, NULL);
        g_print("handler unblocked\n");
    } else {
        g_signal_handlers_block_by_func(button, func, NULL);
        g_print("handler blocked\n");
    }
}

int
main(int argc, char **argv)
{
    GtkWidget *window;
    GtkWidget *button;

    gtk_init(&argc, &argv);

    window = gtk_window_new(GTK_WINDOW_TOPLEVEL);
    button = gtk_button_new_with_label("Click me");

    g_signal_connect_after(button, "clicked", G_CALLBACK(switch_blocking), NULL);
    g_signal_connect(button, "clicked", G_CALLBACK(handler), NULL);

    gtk_container_add(GTK_CONTAINER(window), button);
    gtk_widget_show_all(window);
    gtk_main();

    return 0;
}
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