我有一个类似于这个的数组:
Array
(
[0] => stdClass Object
(
[Leasing] => 12939.74
[Name] => Jeremy
[Rental] => 0
[Sales] => 56603.13
[Total] => 69542.87
)
[1] => stdClass Object
(
[Leasing] => 0
[Name] => Shaun
[Rental] => 0
[Sales] => 58590
[Total] => 58590
)
[2] => stdClass Object
(
[Leasing] => 0
[Name] => Lindsay
[Rental] => 0
[Sales] => 22951.97
[Total] => 22951.97
)
[3] => stdClass Object
(
[Leasing] => 0
[Name] => Sally
[Rental] => 1200
[Sales] => 21624.9
[Total] => 22824.9
)
[4] => stdClass Object
(
[Leasing] => 0
[Name] => House
[Rental] => 0
[Sales] => 16235.81
[Total] => 16235.81
)
[5] => stdClass Object
(
[Leasing] => 5298.85
[Name] => Bill
[Rental] => 1200
[Sales] => 0
[Total] => 6498.85
)
)
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目前,数组按总计排序使用:
usort($data, function ($a, $b) {
return $b->Total - $a->Total;
});
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现在,我需要能够始终将这个人[Name] => House放在阵列的顶部.我的想法是我可以将它排序Total(因为我仍然需要它),然后使用带有House值的元素并将其放在数组的开头.我可以使用特定的KEY并将其置于顶部,但KEY可能会根据总数最高的人而改变.我怎样才能总是把名字命名的人放在House数组顶部?
Tch*_*upi 11
这应该工作:
usort($data, function ($a, $b) {
if ($a->Name != "House" && $b->Name == "House") {
return 1;
} elseif ($a->Name == "House" && $b->Name != "House") {
return -1;
} else {
return $b->Total - $a->Total;
}
});
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如果第一个参数被认为分别小于,等于或大于第二个参数,则比较函数必须返回小于,等于或大于零的整数.
在这种情况下,返回1告诉排序函数,House比任何其他值时,并且-1其House比任何其他值较小.