SQL顺序结果按匹配的字段数

Question

这里有一个复杂的SQL问题.

我目前有一个SELECT语句,它匹配几个字段,像这样.

SELECT field1, field2, field3, field4, field5
FROM table
WHERE field1 = 'variable 1'  
AND field2 = 'variable 2' 
AND field3 = 'variable 3' 
AND field4 = 'variable 4' 
AND field5 = 'variable 5' 

我想修改语句,以便它使用OR而不是AND,以便它选择所有匹配任何字段的记录.

下一步是使用评分系统对结果进行排名.

If field 1 was matched then 1000 is added to the score
If field 2 was matched then 800 is added to the score
If field 3 was matched then 600 is added to the score
If field 4 was matched then 10 is added to the score
If field 5 was matched then 1 is added to the score

所以...

匹配1 - 如果field2和field 3匹配,那么得分将为1400

匹配2 - 如果field1和field 4匹配,那么得分将是1010

匹配1将位于结果的顶部.

任何帮助实现这一点的SQL都非常感激.

Answer 1

尝试:

SELECT
    ....
    FROM ....

    ORDER BY
        (CASE WHEN field1 = 'variable 1' THEN 1000 ELSE 0 END
        +CASE WHEN field2 = 'variable 2' THEN 800 ELSE 0 END
        +CASE WHEN field3 = 'variable 3' THEN 600 ELSE 0 END
        +CASE WHEN field4 = 'variable 4' THEN 10 ELSE 0 END
        +CASE WHEN field5 = 'variable 5' THEN 1 ELSE 0 END
        ) DESC