如何在一个查询中更新两个表？

Question

有没有办法在一个查询中更新两个表？下面是我的代码示例.如何将这两个更新查询合二为一？先感谢您!

   <?php
// DATABASE UPDATE
   if (isset($_POST['submit']) or isset($_GET['submit'])){

// 1st QUERY
   $db =& JFactory::getDBO();
   $query_1 = "UPDATE table_1
                  SET name     = '".$_POST["name"]."',
                      surename = '".$_POST["surename"]."'
               WHERE id=1";
   $db->setQuery($query_1);
   $db->query();

// 2nd QUERY
   $db =& JFactory::getDBO();
   $query_2 = "UPDATE table_2
                  SET team_id   = '".$_POST["team_id"]."',
                  SET team_name = '".$_POST["team_name"]."'
                  ";
   $db->setQuery($query_2);
   $db->query(); } ?>

Answer 1

MySQL实际上允许在单个查询中更新多个表(尽管通常一次一个地执行一个表是有意义的).

UPDATE table_1, table_2
SET table_1.field = <some value>, table_2.field = <some value>
WHERE table_1.field2 = table_2.field_2 
AND table_1.field_3 = <some other value>

请参阅:http://dev.mysql.com/doc/refman/5.1/en/update.html

正如其他人所说,你应该看看使用准备好的陈述.