获取两个字符串之间的字符

Question

我的字符串是:"reply-234-private",我想在"回复"之后和"-private"之前得到号码,它是"234".我尝试使用以下代码,但它返回一个空结果:

$string = 'reply-234-private';
$display = preg_replace('/reply-(.*?)-private/','',$string);
echo $display;

Answer 1

你可以爆炸它:

<?php
$string = 'reply-234-private';
$display = explode('-', $string);

var_dump($display);
// prints array(3) { [0]=> string(5) "reply" [1]=> string(3) "234" [2]=> string(7) "private" }

echo $display[1];
// prints 234

或者,使用preg_match

<?php
$string = 'reply-234-private';
if (preg_match('/reply-(.*?)-private/', $string, $display) === 1) {
    echo $display[1];
}

Answer 2

看看explode()函数

这样的事情:

$myString = 'reply-234-private';

$myStringPartsArray = explode("-", $myString);

$answer = $myStringPartsArray[1];

Answer 3

本文向您展示如何获取两个标记或两个字符串之间的所有字符串.

http://okeschool.com/articles/312/string/how-to-get-of-everything-string-between-two-tag-or-two-strings

<?php
 // Create the Function to get the string
 function GetStringBetween ($string, $start, $finish) {
    $string = " ".$string;
    $position = strpos($string, $start);
    if ($position == 0) return "";
    $position += strlen($start);
    $length = strpos($string, $finish, $position) - $position;
    return substr($string, $position, $length);
}
?>

万一你的问题,你可以试试这个:

$string1='reply-234-private';
echo GetStringBetween ($string1, "-", "-")

或者我们可以使用任何'标识符字符串'来获取标识符字符串之间的字符串.例如:

echo GetStringBetween ($string1, "reply-", "-private")