我想account.bank.statement.line通过其他对象向对象添加行但是我收到此错误:account.bank.statement.line
def action_account_line_create(self, cr, uid, ids):
res = False
cash_id = self.pool.get('account.bank.statement.line')
for exp in self.browse(cr, uid, ids):
company_id = exp.company_id.id
#statement_id = exp.statement_id.id
lines = []
for l in exp.line_ids:
lines.append((0, 0, {
'name': l.name,
'date': l.date,
'amount': l.amount,
'type': l.type,
'statement_id': exp.statement_id.id,
'account_id': l.account_id.id,
'account_analytic_id': l.analytic_account_id.id,
'ref': l.ref,
'note': l.note,
'company_id': l.company_id.id
}))
inv_id = cash_id.create(cr, uid, lines,context=None)
res = inv_id
return res
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我改变了它,但后来我遇到了这个错误:
File "C:\Program Files (x86)\OpenERP 6.1-20121029-003136\Server\server\.\openerp\workflow\wkf_expr.py", line 68, in execute
File "C:\Program Files (x86)\OpenERP 6.1-20121029-003136\Server\server\.\openerp\workflow\wkf_expr.py", line 58, in _eval_expr
File "C:\Program Files (x86)\OpenERP 6.1-20121029-003136\Server\server\.\openerp\tools\safe_eval.py", line 241, in safe_eval
File "C:\Program Files (x86)\OpenERP 6.1-20121029-003136\Server\server\.\openerp\tools\safe_eval.py", line 108, in test_expr
File "<string>", line 0
^
SyntaxError: unexpected EOF while parsing
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码:
def action_account_line_create(self, cr, uid, ids, context=None):
res = False
cash_id = self.pool.get('account.bank.statement.line')
for exp in self.browse(cr, uid, ids):
company_id = exp.company_id.id
lines = []
for l in exp.line_ids:
res = cash_id.create ( cr, uid, {
'name': l.name,
'date': l.date,
'amount': l.amount,
'type': l.type,
'statement_id': exp.statement_id.id,
'account_id': l.account_id.id,
'account_analytic_id': l.analytic_account_id.id,
'ref': l.ref,
'note': l.note,
'company_id': l.company_id.id
}, context=None)
return res
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MBa*_*rsi 72
由于您尝试dict使用错误的序列(list或tuple)结构更新对象,因此引发此错误.
cash_id.create(cr, uid, lines,context=None)试图转换lines成dict对象:
(0, 0, {
'name': l.name,
'date': l.date,
'amount': l.amount,
'type': l.type,
'statement_id': exp.statement_id.id,
'account_id': l.account_id.id,
'account_analytic_id': l.analytic_account_id.id,
'ref': l.ref,
'note': l.note,
'company_id': l.company_id.id
})
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从该元组中删除第二个零以将其正确转换为dict对象.
要测试你的自己,试试这个到python shell:
>>> l=[(0,0,{'h':88})]
>>> a={}
>>> a.update(l)
Traceback (most recent call last):
File "<pyshell#11>", line 1, in <module>
a.update(l)
ValueError: dictionary update sequence element #0 has length 3; 2 is required
>>> l=[(0,{'h':88})]
>>> a.update(l)
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Ian*_*hel 11
我用错误的语法更新字典时遇到此错误:
试试这些:
lineItem.values.update({attribute,value})
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代替
lineItem.values.update({attribute:value})
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Jor*_*ren 11
这并不是具体问题的答案,但如果还有其他人,比如我,在 fastAPI 中遇到此错误并最终出现在这里:
这可能是因为您的路由响应具有无法通过 JSON 序列化的值jsonable_encoder。对我来说是 WKBElement:https://github.com/tiangolo/fastapi/issues/2366
就像在这个问题中一样,我最终只是从输出中删除了该值。
从等长元组创建 dict 的快速方法之一:
>>> t1 = (a,b,c,d)
>>> t2 = (1,2,3,4)
>>> dict(zip(t1, t2))
{'a':1, 'b':2, 'c':3, 'd':4, }
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