0 java string keyboard methods
我正在研究我的问题,这是一个非常简单的问题......
基本的101购物车,产品清单硬编码(仅限实践问题 - 我明白这不是真正的做法)
我希望用户输入一个字符串 - 产品代码,然后从Description方法返回相关产品的描述
它返回一个0值,即方法中的if语句似乎没有识别用户输入的String.
硬编码的字符串工作 - 键盘输入字符串不是我难倒,但我想我只是缺少一些基本的东西
import java.util.*;
class CW1ShoppingCart1_2ShowProdAndGetChoice
{
public static void main(String[] args)
{
/*PART 1 Offer catalogue and get user choice*/
System.out.println("ITEMS AVAIALBLE TODAY: \n");
System.out.print("P4383"+ "\t"+ CW1ShoppingCart1GetProductDetails.Description("P4383"));
System.out.println("\t"+ "$"+ CW1ShoppingCart1GetProductDetails.Price("P4383"));
System.out.print("P4385"+ "\t"+ CW1ShoppingCart1GetProductDetails.Description("P4385"));
System.out.println("\t"+ "$"+ CW1ShoppingCart1GetProductDetails.Price("P4385"));
System.out.print("P4387"+ "\t"+ CW1ShoppingCart1GetProductDetails.Description("P4387"));
System.out.println("\t"+ "$"+ CW1ShoppingCart1GetProductDetails.Price("P4387"));
System.out.println("\nTO START SHOPPING ENTER A PRODUCT CODE AND HIT RETURN \n");
Scanner in = new Scanner (System.in);
String ProdCode =in.nextLine();
System.out.println("You Chose: "+ CW1ShoppingCart1GetProductDetails.Description(ProdCode));
}
}
class CW1ShoppingCart1GetProductDetails
{
static String Description(String ProdCode)
{
String Proddesc;
if(ProdCode=="P4387")Proddesc = "Little used helper monkey - 1 ";
else if(ProdCode=="P4385") Proddesc = "Chilli chocolate - 100g ";
else if(ProdCode=="P4383") Proddesc = "State-owned Bank - real value - 1 entity ";
else Proddesc = "0";
return Proddesc;
}
static double Price(String ProdCode)
{
double ProdPrice;
if(ProdCode=="P4387") ProdPrice = 1200;
else if(ProdCode=="P4385") ProdPrice = 3.27;
else if(ProdCode=="P4383") ProdPrice = -0.08;
else ProdPrice = 0;
return ProdPrice;
}
}
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gef*_*fei 10
问题是你==用来比较字符串.请equals改用.
if(ProdCode.equals("P4387"))Proddesc = "Little used helper monkey - 1 ";
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等等