Nat*_*ati 2 sql oracle outer-join
假设我有5个表,如下所示:
CREATE TABLE T1 (
FIRST_NAME VARCHAR2(100),
LAST_NAME VARCHAR2(100),
CITY NUMERIC,
SALARY NUMERIC);
CREATE TABLE T2 (
CITY NUMERIC,
DISTRICT NUMERIC);
CREATE TABLE T3 (
DISTRICT NUMERIC,
DOMAIN NUMERIC);
CREATE TABLE T4 (
DOMAIN NUMERIC,
DETAILS_BOOK NUMERIC);
CREATE TABLE T5 (
DETAILS_BOOK NUMERIC,
FIRST_NAME VARCHAR2(100),
LAST_NAME VARCHAR2(100),
EMAIL VARCHAR2(100));
INSERT INTO T1 VALUES ('john', 'doe',1001,1000);
INSERT INTO T1 VALUES ('jack', 'jill',1001,2000);
INSERT INTO T1 VALUES ('jeff', 'bush',1001,1500);
INSERT INTO T2 VALUES (1001,1);
INSERT INTO T3 VALUES (1,543);
INSERT INTO T4 VALUES (543,22);
INSERT INTO T5 VALUES (22,'john', 'doe','john@22.com');
INSERT INTO T5 VALUES (44,'john', 'doe','john@44.com');
INSERT INTO T5 VALUES (22,'jeff', 'bush','jeff@22.com');
INSERT INTO T5 VALUES (44,'jeff', 'bush','jeff@44.com');
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现在,我想要来自t1的所有记录,包括他们的工资和电子邮件,对应于表t2,t3和t4,这样reuslt应该是:
FIRST_NAME | LAST_NAME | SALARY | EMAIL
--------------------------------------------------
john | doe | 1000 | john@22.com
jeff | bush | 1500 | jeff@22.com
jack | jill | 2000 | (NULL)
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到目前为止我得到的是:
SELECT T1.FIRST_NAME, T1.LAST_NAME,T1.SALARY,T5.EMAIL
FROM T1,T2,T3,T4,T5
WHERE T1.FIRST_NAME = T5.FIRST_NAME (+)
and T1.LAST_NAME = T5.LAST_NAME(+)
AND T1.CITY = T2.CITY
AND T2.DISTRICT = T3.DISTRICT
AND T3.DOMAIN = T4.DOMAIN
AND T4.DETAILS_BOOK = T5.DETAILS_BOOK
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它只返回前两行.
Mah*_*mal 10
试试这个:
SELECT
T1.FIRST_NAME,
T1.LAST_NAME,
T1.SALARY,
T5.EMAIL
FROM T1
LEFT JOIN T2 ON T1.CITY = T2.CITY
LEFT JOIN T3 ON T2.DISTRICT = T3.DISTRICT
LEFT JOIN T4 ON T3.DOMAIN = T4.DOMAIN
LEFT JOIN T5 ON T4.DETAILS_BOOK = T5.DETAILS_BOOK
AND T1.FIRST_NAME = T5.FIRST_NAME
AND T1.LAST_NAME = T5.LAST_NAME;
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这会给你:
| FIRST_NAME | LAST_NAME | SALARY | EMAIL |
-------------------------------------------------
| john | doe | 1000 | john@22.com |
| jeff | bush | 1500 | jeff@22.com |
| jack | jill | 2000 | (null) |
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问题是,使得你的连接INNER JOIN之后的OUTER JOIN工作就像一个INNER,因为,内部连接消除了来自外连接的那些不匹配的行.
请注意:我使用了ANSI SQL-92显式LEFT OUTER JOIN语法,而不是您在查询中使用的旧隐式OUTER和INNER连接语法.
请尝试使用LEFT OUTER JOIN而不是旧的外连接语法,并避免INNER JOIN在OUTER JOINs 之后.
有关详细信息,请参阅:
更新:
当FROM子句中有多个表引用时JOIN,每个表都与下一个表连接,从FROM第1个句子开始,结果是临时结果集,然后这个临时结果集与下一个表连接,依此类推.如果是 OUTER JOIN,有左或右:
LEFT JOIN 将包括左表中那些不匹配的行,其中,RIGHT JOIN 将包括右表中那些不匹配的行.根据您要选择的数据,您必须在JOIN操作员的两侧以及它们的顺序中注意这些表.
1:这只是逻辑查询处理顺序,但实际顺序始终取决于查询优化器.
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