如何在JSP错误页面中显示请求的URL?

3 java jsp servlets custom-error-pages

在错误页面中,我想显示用户请求的URL.

在我的web.xml中:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xmlns="http://java.sun.com/xml/ns/javaee"
        xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
        xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
                            http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
        id="WebApp_ID"
        version="3.0">

    <display-name>MyStuff</display-name>

    <error-page>
        <error-code>404</error-code>
        <location>/WEB-INF/error-404.jsp</location>
    </error-page>

</web-app>
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这将转发到error-404.jsp,这是该文件的内容:

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
    "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
    <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
    <title>Page Not found</title>
</head>
<body>
    <p align="center">
    <%
        out.println("Requested resource: " + request.getRequestURL()+ " not found");
    %>
</body>
</html>
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问题是request.getRequestURL()需要更改,但不知道搜索内容的关键字.

当我启动浏览器时,http://localhost:8080/MyStuff我收到以下错误:

Requested resource: http://localhost:8080/MyStuff/WEB-INF/error-404.jsp not found

怎么解决这个?

inf*_*k01 7

以下是JSP错误页面的一个简单示例,它显示了错误代码和请求页面的URL:

404.jsp:

<%@ page language="java" isErrorPage="true" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
    <title>Error page</title>
    <meta charset="utf-8">
</head>
<body>
    <button onclick="history.back()">Back to Previous Page</button>
    <h1>404 Page Not Found.</h1>
    <br />
    <p><b>Error code:</b> ${pageContext.errorData.statusCode}</p>
    <p><b>Request URI:</b> ${pageContext.request.scheme}://${header.host}${pageContext.errorData.requestURI}</p>
    <br />
</body>
</html>
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有用的阅读:

PS
强烈建议不要在JSP中使用scriptlet.阅读这篇文章.