Rob*_*Rob 5 javascript regex string json object
我有一个 JSON 对象,它作为字符串传递给我,但字符串形式的对象包含重复的属性。我需要临时向属性添加递增数字,以避免出现重复 JSON 属性的问题。完成对象编辑后,我会将对象 JSON.Stringify 恢复为字符串并删除数字。
这是我传递的字符串:
{
"View":{
"Image":{
"BackgroundImage":"Image.png",
"Position":[0,0],
"Width":320,
"Height":480
},
"Button":{
"BackgroundImage":"ButtonTop.png",
"Position":[61,83],
"Width":217,
"Height":58
},
"Button":{
"BackgroundImage":"ButtonBottom.png",
"Position":[61,214],
"Width":205,
"Height":73
},
"TextField":{
"BackgroundImage":"TextFieldLogin.png",
"Position":[102,336],
"Width":189,
"Height":31
},
"Label":{
"Position":[137,100],
"Width":72,
"Height":20,
"Text":"Hi Steve",
"FontSize":18,
"Color":[0,0,0,1]
},
"Label":{
"Position":[43,342],
"Width":54,
"Height":20,
"Text":"Login:",
"FontSize":18,
"Color":[0,0,0,1]
},
"Label":{
"Position":[115,234],
"Width":54,
"Height":20,
"Text":"Button",
"FontSize":18,
"Color":[0,0,0,1]
}
}
}
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我希望输出如下:
{
"View_1":{
"Image_1":{
"BackgroundImage":"Image.png",
"Position":[0,0],
"Width":320,
"Height":480
},
"Button_1":{
"BackgroundImage":"ButtonTop.png",
"Position":[61,83],
"Width":217,
"Height":58
},
"Button_2":{
"BackgroundImage":"ButtonBottom.png",
"Position":[61,214],
"Width":205,
"Height":73
},
"TextField_1":{
"BackgroundImage":"TextFieldLogin.png",
"Position":[102,336],
"Width":189,
"Height":31
},
"Label_1":{
"Position":[137,100],
"Width":72,
"Height":20,
"Text":"Hi Steve",
"FontSize":18,
"Color":[0,0,0,1]
},
"Label_2":{
"Position":[43,342],
"Width":54,
"Height":20,
"Text":"Login:",
"FontSize":18,
"Color":[0,0,0,1]
},
"Label_3":{
"Position":[115,234],
"Width":54,
"Height":20,
"Text":"Button",
"FontSize":18,
"Color":[0,0,0,1]
}
}
}
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如何使用 javascript .replace() 按需添加编号,然后按需删除编号?
这个怎么样?我同意这里的其他声音,建议提供此“JSON”的人负责提供有效的语法,但排除这种可能性,这可能会让您开始:
function formatJSON(input) {
return input.replace(/"([^"]+?)":{(.+)}/g, function(string, key, value) {
var dict = {};
return '"' + key + '":{' + value.replace(/"([^"]+?)":{(.+?)}/g, function(string, key, value) {
dict[key] = dict[key] == undefined ? 1 : ++dict[key];
return '"' + key + '_' + dict[key] + '":{' + formatJSON(value) + '}';
}) + '}';
});
};
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JSFiddle: http: //jsfiddle.net/WYkAT/
请注意,这将无法重命名更复杂、更深的 JSON 字符串上的所有键。它可以很容易地修改为更加递归并且不太特定于您的特定情况,但可能会导致一些性能下降。如果您需要一个成熟的解决方案,我会考虑修改现有的 JSON.parse polyfill。这里有两个(JSON2 和 JSON3):