如何在java应用程序上下文中使用spring MVC的<mvc:resources>标记？

Question

我已经创建了"for now"一个简单而基本的Spring Web应用程序.我习惯将部署描述符作为简单的web.xml文件,然后将应用程序上下文作为xml文件.

虽然,现在我想尝试仅使用java文件创建我的整个spring Web应用程序.因此,我创建了我的WebApplicationInitializer,而不是正常的部署描述符,以及使用@Configuration批注的应用程序上下文.

部署描述符

package dk.chakula.config;

import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.ServletRegistration.Dynamic;
import org.springframework.web.WebApplicationInitializer;
import org.springframework.web.context.WebApplicationContext;
import org.springframework.web.context.support.AnnotationConfigWebApplicationContext;
import org.springframework.web.servlet.DispatcherServlet;
/**
 *
 * @author martin
 * @since 12-1-2012
 * @version 1.0
 */
public class Initializer implements WebApplicationInitializer {

    @Override
    public void onStartup(ServletContext servletContext)
            throws ServletException {
        registerDispatcherServlet(servletContext);
    }

    private void registerDispatcherServlet(final ServletContext servletContext) {
        WebApplicationContext dispatcherContext = createContext(ChakulaWebConfigurationContext.class);
        DispatcherServlet dispatcherServlet = new DispatcherServlet(dispatcherContext);
        Dynamic dispatcher = servletContext.addServlet("dispatcher", dispatcherServlet);
        dispatcher.setLoadOnStartup(1);
        dispatcher.addMapping("/");
    }

    private WebApplicationContext createContext(final Class<?>... annotatedClasses) {
        AnnotationConfigWebApplicationContext context = new AnnotationConfigWebApplicationContext();
        context.register(annotatedClasses);
        return context;
    }

} //End of class Initializer

应用背景

package dk.chakula.config;

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.view.UrlBasedViewResolver;
import org.springframework.web.servlet.view.tiles2.TilesConfigurer;
import org.springframework.web.servlet.view.tiles2.TilesView;

/**
 *
 * @author martin
 * @since 12-01-2013
 * @version 1.0
 */
@Configuration
@EnableWebMvc
@ComponentScan("dk.chakula.web")
public class ChakulaWebConfigurationContext {

    @Bean
    public TilesConfigurer setupTilesConfigurer() {
        TilesConfigurer configurer = new TilesConfigurer();
        String[] definitions = {"/layout/layout.xml"};
        configurer.setDefinitions(definitions);
        return configurer;
    }

    @Bean
    public UrlBasedViewResolver setupTilesViewResolver() {
        UrlBasedViewResolver viewResolver = new UrlBasedViewResolver();
        viewResolver.setViewClass(TilesView.class);
        return viewResolver;
    }

} //End of class ChakulaWebConfigurationContext

我的问题是,我似乎无法找到一种方法'隔离'我的映射到包含图像,css javascript等资源文件夹.当我的应用程序上下文是在java中.

使用普通的XML应用程序上下文,我使用此标记将映射隔离到/ resources /

<mvc:resources mapping="/resources/**" location="/resources/" />

我该怎么做,所以我的网络应用程序可以使用我的图像,CSS等.

Answer 1

为了能够在Spring MVC应用程序中提供静态资源,您需要两个XML标记:<mvc:resources/>和<mvc:default-servlet-handler/>.基于Java的Spring配置中的相同内容如下:

@Configuration
@EnableWebMvc
public class WebMvcConfig extends WebMvcConfigurerAdapter {

    // equivalents for <mvc:resources/> tags
    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("/css/**").addResourceLocations("/css/").setCachePeriod(31556926);
        registry.addResourceHandler("/img/**").addResourceLocations("/img/").setCachePeriod(31556926);
        registry.addResourceHandler("/js/**").addResourceLocations("/js/").setCachePeriod(31556926);
    }

    // equivalent for <mvc:default-servlet-handler/> tag
    @Override
    public void configureDefaultServletHandling(DefaultServletHandlerConfigurer configurer) {
        configurer.enable();
    }

    // ... other stuff ...
}

请注意,由于使用了@EnableWebMvc注释,因此无需直接扩展WebMvcConfigurationSupport,您只需要扩展即可WebMvcConfigurerAdapter.有关详细信息,请参阅@EnableWebMvc的JavaDoc.

Answer 2

在互联网上使用数小时搜索只使用java文件的Spring MVC 3后,我查看了一些文章,这些文章使用了从WebMvcConfigurationSupport类扩展的方法,然后重写了2个方法 - addResourceHandler(ResourceHandlerRegistry)和ResourceHandlerMapping().

我现在的新应用程序上下文如下所示.

package dk.chakula.config;

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.HandlerMapping;
import org.springframework.web.servlet.config.annotation.EnableWebMvc;
import org.springframework.web.servlet.config.annotation.ResourceHandlerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurationSupport;
import org.springframework.web.servlet.handler.AbstractHandlerMapping;
import org.springframework.web.servlet.view.UrlBasedViewResolver;
import org.springframework.web.servlet.view.tiles2.TilesConfigurer;
import org.springframework.web.servlet.view.tiles2.TilesView;

/**
 *
 * @author martin
 * @since 12-01-2013
 * @version 1.0
 */
@Configuration
@EnableWebMvc
@ComponentScan("dk.chakula.web")
public class ChakulaWebConfigurationContext extends WebMvcConfigurationSupport {

    @Override
    public void addResourceHandlers(ResourceHandlerRegistry registry) {
        registry.addResourceHandler("/resources/**").addResourceLocations("/resources/");
    }

    @Override
    @Bean
    public HandlerMapping resourceHandlerMapping() {
        AbstractHandlerMapping handlerMapping = (AbstractHandlerMapping) super.resourceHandlerMapping();
        handlerMapping.setOrder(-1);
        return handlerMapping;
    }

    @Bean
    public TilesConfigurer setupTilesConfigurer() {
        TilesConfigurer configurer = new TilesConfigurer();
        String[] definitions = {"/layout/layout.xml"};
        configurer.setDefinitions(definitions);
        return configurer;
    }

    @Bean
    public UrlBasedViewResolver setupTilesViewResolver() {
        UrlBasedViewResolver viewResolver = new UrlBasedViewResolver();
        viewResolver.setViewClass(TilesView.class);
        return viewResolver;
    }

} //End of class ChakulaWebConfigurationContext

据我所知,我们必须覆盖addResourceHandler,以添加位置和资源到注册表的映射.此后我们需要一个返回HandlerMapping对象的bean.此HandlerMapping的顺序应设置为-1,因为我可以从spring文档中读取,然后-1表示

HandlerMapping以Integer.MAX_VALUE-1排序,以提供静态资源请求.

我的应用程序现在可以将css文件和图像加载到他们的视图中,我想通过答案启发其他人,以便将来的人可以从中受益.