我正在尝试使用以下代码在Tridion模板类中创建多媒体组件.
MemoryStream stringInMemoryStream = new MemoryStream(ASCIIEncoding.Default.GetBytes("
<test>testing</test>"));
Component xmlMultimediaComponent = new Component(engine.GetSession(), new
TcmUri("tcm:21-2008-2"));
xmlMultimediaComponent.Title = "New MM component";
xmlMultimediaComponent.Schema = new Schema(new TcmUri("tcm:10-6532-8"),
engine.GetSession());
xmlMultimediaComponent.BinaryContent.MultimediaType = new MultimediaType(new
TcmUri("tcm:0-36-65544"), engine.GetSession());
xmlMultimediaComponent.BinaryContent.MultimediaType.MimeType = "application/xml";
xmlMultimediaComponent.BinaryContent.MultimediaType.FileExtensions = new List<string>
{"xml", "XML"};
xmlMultimediaComponent.BinaryContent.UploadFromStream = stringInMemoryStream;
xmlMultimediaComponent.BinaryContent.Filename = "testing.xml".ToLower();
xmlMultimediaComponent.Save();
xmlMultimediaComponent.CheckIn(true);
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请注意,"tcm:21-2008-2"是必须创建组件的文件夹TCM ID."tcm:10-6532-8"是多媒体模式ID,"tcm:0-36-65544"是多媒体类型ID.
然而,似乎有一些问题,它失败了以下错误:
链接到Schema具有无效值.在Tridion.ContentManager.Utilities.ThrowInvalidLinkException(链路链接,KernelException的InnerException)在Tridion.ContentManager.IdentifiableObject.AssertValidLink(链路链接)在Tridion.ContentManager.IdentifiableObject.AssertValidLinks(IEnumerable`1链接)在Tridion.ContentManager.IdentifiableObject.AssertValidLinks( )Tridion.ContentManager.ContentManager.OnSaving(SaveEventArgs eventArgs)位于Tridion.ContentManager.ContentManager.ContentManager上的Tridion.ContentManager.ContentManagement.VersionedItem.OnSaving(SaveEventArgs eventArgs)中的Tridion.ContentManager.IdentifiableObject.OnSaving(SaveEventArgs eventArgs)处于Tridion.ContentManager.OnSaving(SaveEventArgs eventArgs).在Tridion.ContentManager.IdentifiableObject.Save(SaveEventArgs EventArgs的)在Tridion.ContentManager.ContentManagement.VersionedItem.Save(布尔checkInAfterSave)在Tridion.ContentManager.ContentManagement.VersionedItem.Save OnSaving(SaveEventArgs EventArgs的)()
上述错误发生在以下声明中xmlMultimediaComponent.Save().
任何想法我们如何将LinkToMultimedia类型模式ID传递给多媒体组件?
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