如何旋转任何程度的图像?

Dan*_*Lip 10 c#

我有动画gif和我使用类来解析它的图像(帧).这堂课是:

using System;
using System.Drawing;
using System.Drawing.Imaging;
using System.Collections.Generic;
using System.IO;

public class AnimatedGif
{
    private List<AnimatedGifFrame> mImages = new List<AnimatedGifFrame>();
    public AnimatedGif(string path)
    {
        Image img = Image.FromFile(path);
        int frames = img.GetFrameCount(FrameDimension.Time);
        if (frames <= 1) throw new ArgumentException("Image not animated");
        byte[] times = img.GetPropertyItem(0x5100).Value;
        int frame = 0;
        for (; ; )
        {
            int dur = BitConverter.ToInt32(times, 4 * frame);
            mImages.Add(new AnimatedGifFrame(new Bitmap(img), dur));
            if (++frame >= frames) break;
            img.SelectActiveFrame(FrameDimension.Time, frame);
        }
        img.Dispose();
    }
    public List<AnimatedGifFrame> Images { get { return mImages; } }
}

public class AnimatedGifFrame
{
    private int mDuration;
    private Image mImage;
    internal AnimatedGifFrame(Image img, int duration)
    {
        mImage = img; mDuration = duration;
    }
    public Image Image { get { return mImage; } }
    public int Duration { get { return mDuration; } }
}
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现在在form1中,我在这种情况下循环遍历帧4,我希望以任何角度旋转动画.现在它每转45或90度.我想为动画添加更多帧(图像),所以如果我将旋转设置为31或10度,那么我将看到动画旋转10度.

这是Form1中的代码,它不能正常工作.我使用旋转功能,我没有测试,如果它的任何工作.

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace AnimatedGifEditor
{
    public partial class Form1 : Form
    {
        Image myImage;
        AnimatedGif myGif;
        Bitmap bitmap;

        public Form1()
        {
            InitializeComponent();

            myImage = Image.FromFile(@"D:\fananimation.gif");
            myGif = new AnimatedGif(@"D:\fananimation.gif");
            for (int i = 0; i < myGif.Images.Count; i++)
            {
                pictureBox1.Image = myGif.Images[3].Image;
                bitmap = new Bitmap(pictureBox1.Image);
                rotateImage(bitmap, 76);
                pictureBox1.Image = bitmap;
            }


        }

        private void Form1_Load(object sender, EventArgs e)
        {

        }



private Bitmap RotateImg(Bitmap bmp, float angle, Color bkColor)
    {
        int w = bmp.Width;
        int h = bmp.Height;
        bmp.PixelFormat pf = default(bmp.PixelFormat);
        if (bkColor == Color.Transparent)
        {
            pf = bmp.Format32bppArgb;
        }
        else
        {
            pf = bmp.PixelFormat;
        }

        Bitmap tempImg = new Bitmap(w, h, pf);
        Graphics g = Graphics.FromImage(tempImg);
        g.Clear(bkColor);
        g.DrawImageUnscaled(bmp, 1, 1);
        g.Dispose();

        GraphicsPath path = new GraphicsPath();
        path.AddRectangle(new RectangleF(0f, 0f, w, h));
        Matrix mtrx = new Matrix();
        //Using System.Drawing.Drawing2D.Matrix class 
        mtrx.Rotate(angle);
        RectangleF rct = path.GetBounds(mtrx);
        Bitmap newImg = new Bitmap(Convert.ToInt32(rct.Width), Convert.ToInt32(rct.Height), pf);
        g = Graphics.FromImage(newImg);
        g.Clear(bkColor);
        g.TranslateTransform(-rct.X, -rct.Y);
        g.RotateTransform(angle);
        g.InterpolationMode = InterpolationMode.HighQualityBilinear;
        g.DrawImageUnscaled(tempImg, 0, 0);
        g.Dispose();
        tempImg.Dispose();
        return newImg;
    }
    }
}
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可以在这里找到用于测试的动画gif:

在此输入图像描述

Oma*_*mar 21

我不明白你的问题是什么,但我认为你的代码可以改进.我认为你不需要直接使用这个Matrix类.有一些功能可以帮助您.事实上,您唯一需要的是:将旋转点设置为中心,旋转图形并在其上绘制,使用Graphics类的某些功能.因此,要旋转图像,您可以使用以下简单代码:

private Bitmap RotateImage(Bitmap bmp, float angle) {
     Bitmap rotatedImage = new Bitmap(bmp.Width, bmp.Height);
     using (Graphics g = Graphics.FromImage(rotatedImage)) {
        // Set the rotation point to the center in the matrix
        g.TranslateTransform(bmp.Width / 2, bmp.Height / 2);
        // Rotate
        g.RotateTransform(angle);
        // Restore rotation point in the matrix
        g.TranslateTransform(- bmp.Width / 2, - bmp.Height / 2);
        // Draw the image on the bitmap
        g.DrawImage(bmp, new Point(0, 0));
     }

     return rotatedImage;
}
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小智 7

我自己尝试了@Omar 的答案并意识到,原始图像在两侧被剪掉了......我已经重写了它,因此它将图像调整为新尺寸:

private static Bitmap RotateImage(Bitmap bmp, float angle)
{
    float alpha = angle;

    //edit: negative angle +360
    while(alpha <0) alpha +=360;

    float gamma = 90;
    float beta = 180 - angle - gamma;

    float c1 = bmp.Height;
    float a1 = (float)(c1 * Math.Sin(alpha * Math.PI / 180) / Math.Sin(gamma * Math.PI / 180));
    float b1 = (float)(c1 * Math.Sin(beta * Math.PI / 180) / Math.Sin(gamma * Math.PI / 180));

    float c2 = bmp.Width;
    float a2 = (float)(c2 * Math.Sin(alpha * Math.PI / 180) / Math.Sin(gamma * Math.PI / 180));
    float b2 = (float)(c2 * Math.Sin(beta * Math.PI / 180) / Math.Sin(gamma * Math.PI / 180));

    int width = Convert.ToInt32(b2 + a1);
    int height = Convert.ToInt32(b1 + a2);

    Bitmap rotatedImage = new Bitmap(width, height);
    using (Graphics g = Graphics.FromImage(rotatedImage))
    {
        g.TranslateTransform(rotatedImage.Width / 2, rotatedImage.Height / 2); //set the rotation point as the center into the matrix
        g.RotateTransform(angle); //rotate
        g.TranslateTransform(-rotatedImage.Width / 2, -rotatedImage.Height / 2); //restore rotation point into the matrix
        g.DrawImage(bmp, new Point((width - bmp.Width) / 2, (height - bmp.Height) / 2)); //draw the image on the new bitmap
    }
    return rotatedImage;
}
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半径 30 度处的尺寸变化


小智 6

根据先前的答案,我创建了此代码,该代码不会剪切图像(其他示例对我不起作用)

    private Bitmap RotateImage(Bitmap bmp, float angle)
    {
        float height = bmp.Height;
        float width = bmp.Width;
        int hypotenuse = System.Convert.ToInt32(System.Math.Floor(Math.Sqrt(height * height + width * width)));
        Bitmap rotatedImage = new Bitmap(hypotenuse, hypotenuse);
        using (Graphics g = Graphics.FromImage(rotatedImage))
        {
            g.TranslateTransform((float)rotatedImage.Width / 2, (float)rotatedImage.Height / 2); //set the rotation point as the center into the matrix
            g.RotateTransform(angle); //rotate
            g.TranslateTransform(-(float)rotatedImage.Width / 2, -(float)rotatedImage.Height / 2); //restore rotation point into the matrix
            g.DrawImage(bmp, (hypotenuse - width) / 2, (hypotenuse - height) / 2, width, height);
        }
        return rotatedImage;
    }
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Raj*_*esh 5

您是否尝试过RotateFlip?

public partial class Form1 : Form
{
    Image myImage;
    AnimatedGif myGif;
    Bitmap bitmap;
    public Form1()
    {
        InitializeComponent();
        myImage = Image.FromFile(@"D:\fananimation.gif");
        bitmap = new Bitmap(myImage);
        bitmap.RotateFlip(System.Drawing.RotateFlipType.Rotate90FlipNone);
        this.pictureBox1.Image = bitmap;
    }

}
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资源

  • RotateFlip() 方法工作正常,但只有少数默认翻转类型,如果您想模拟具有流体运动的 gif,则此方法无法工作。 (2认同)