我是C的新手.我试图从一个函数返回一个二维数组.就是这样的
int *MakeGridOfCounts(int Grid[][6])
{
int cGrid[6][6] = {{0, }, {0, }, {0, }, {0, }, {0, }, {0, }};
int (*p)[6] = cGrid;
return (int*)p;
}
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我知道这会导致错误,需要帮助.谢谢
ana*_*lyg 19
C语言有一个基本缺陷:不可能从函数返回数组.这有很多变通方法; 我将描述三个.
返回指针而不是数组本身.这导致了C中的另一个问题:当一个函数返回指向某个东西的指针时,它通常应该动态地分配一些东西.你不应该忘记稍后解除分配(当不再需要数组时).
typedef int (*pointer_to_array)[6][6];
pointer_to_array workaround1()
{
pointer_to_array result = malloc(sizeof(*result));
(*result)[0][0] = 0;
(*result)[1][0] = 0;
(*result)[2][0] = 0;
(*result)[3][0] = 0;
(*result)[4][0] = 0;
(*result)[5][0] = 0;
return result;
}
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二维数组在内存中显示为一系列数字,因此您可以通过指向第一个元素的指针替换它.您明确声明要返回一个数组,但是您的示例代码返回一个指向int的指针,因此您可以相应地更改其余代码.
int *workaround2()
{
int temp[6][6] = {{0}}; // initializes a temporary array to zeros
int *result = malloc(sizeof(int) * 6 * 6); // allocates a one-dimensional array
memcpy(result, temp, sizeof(int) * 6 * 6); // copies stuff
return result; // cannot return an array but can return a pointer!
}
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听起来很傻,但功能可以返回结构,即使它们不能返回数组!即使返回的结构包含数组.
struct array_inside
{
int array[6][6];
};
struct array_inside workaround3()
{
struct array_inside result = {{{0}}};
return result;
}
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Ric*_*III -2
试试这个,在我的 mac 上用 GCC 编译得很好。
typedef struct _intGrid_t{
int **data;
int width;
int height;
} *IntGrid;
IntGrid makeGridWithSize(int width, int height);
IntGrid makeGridWithSize(int width, int height)
{
IntGrid grid = malloc(sizeof(struct _intGrid_t));
int **data = (int **) malloc(sizeof(int *) * width);
for (int i = 0; i < width; i++) {
data[i] = malloc(sizeof(int) * height);
memset(data[i], 0, sizeof(int) * height);
}
grid->data = data;
grid->width = width;
grid->height = height;
return grid;
}
void printGrid(IntGrid grid);
void printGrid(IntGrid grid)
{
printf(" { \n");
for (int i =0; i < grid->width; i++) {
printf(" { ");
for (int j = 0; j < grid->height; j++) {
printf("%i", grid->data[i][j]);
if (j != grid->height - 1)
{
printf(", ");
}
}
printf(" } \n");
}
printf(" } \n");
}
void freeGrid(IntGrid grid);
void freeGrid(IntGrid grid)
{
for (int i = 0; i < grid->width; i++) {
free(grid->data[i]);
}
free(grid->data);
free(grid);
}
int main (int argc, const char * argv[])
{
srand((int) time(NULL));
IntGrid grid = makeGridWithSize(10, 10);
for (int i = 0; i < grid->width; i++) {
for (int j = 0; j < grid->height; j++) {
grid->data[i][j] = rand() % 10;
}
}
printGrid(grid);
freeGrid(grid);
return 0;
}
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