将数据附加到POST NSURLRequest

Question

如何将数据附加到现有数据POST NSURLRequest？我需要添加一个新参数userId=2323.

Answer 1

如果您不想使用第三方课程,那么以下是您设置帖子正文的方法......

NSURL *aUrl = [NSURL URLWithString:@"http://www.apple.com/"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:aUrl
                                         cachePolicy:NSURLRequestUseProtocolCachePolicy
                                     timeoutInterval:60.0];

[request setHTTPMethod:@"POST"];
NSString *postString = @"company=Locassa&quality=AWESOME!";
[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];

NSURLConnection *connection= [[NSURLConnection alloc] initWithRequest:request 
                                                             delegate:self];

只需将您的键/值对附加到帖子字符串即可

Answer 2

NSMutableURLRequest必须在致电之前进行所有更改NSURLConnection.

我看到这个问题,因为我复制并粘贴上面的代码并运行TCPMon,看到请求GET而不是预期的POST.

NSURL *aUrl = [NSURL URLWithString:@"http://www.apple.com/"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:aUrl
                                     cachePolicy:NSURLRequestUseProtocolCachePolicy
                                 timeoutInterval:60.0];


[request setHTTPMethod:@"POST"];
NSString *postString = @"company=Locassa&quality=AWESOME!";
[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];

NSURLConnection *connection= [[NSURLConnection alloc] initWithRequest:request 
                                                         delegate:self];

Answer 3

关于形成POST请求的先前帖子在很大程度上是正确的(将参数添加到正文,而不是URL).但是如果输入数据有可能包含任何保留字符(例如空格,符号,加号),那么您将需要处理这些保留字符.也就是说,你应该百分之百地逃避输入.

//create body of the request

NSString *userid = ...
NSString *encodedUserid = [self percentEscapeString:userid];
NSString *postString    = [NSString stringWithFormat:@"userid=%@", encodedUserid];
NSData   *postBody      = [postString dataUsingEncoding:NSUTF8StringEncoding];

//initialize a request from url

NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPBody:postBody];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

//initialize a connection from request, any way you want to, e.g.

NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];

其中precentEscapeString方法被定义如下:

- (NSString *)percentEscapeString:(NSString *)string
{
    NSString *result = CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,
                                                                                 (CFStringRef)string,
                                                                                 (CFStringRef)@" ",
                                                                                 (CFStringRef)@":/?@!$&'()*+,;=",
                                                                                 kCFStringEncodingUTF8));
    return [result stringByReplacingOccurrencesOfString:@" " withString:@"+"];
}

请注意,有一种很有前景的NSString方法stringByAddingPercentEscapesUsingEncoding(现已弃用),它做了非常相似的事情,但却抵制使用它的诱惑.它处理一些字符(例如空格字符),但不处理其他字符(例如字符+或&字符).

当代的等价物stringByAddingPercentEncodingWithAllowedCharacters,但是,再次,不要试图使用URLQueryAllowedCharacterSet,因为这也允许+和&传递未转义.这两个字符在更广泛的"查询"中是允许的,但如果这些字符出现在查询中的值内,则必须对其进行转义.从技术上讲,您可以使用URLQueryAllowedCharacterSet构建可变字符集并删除它们中包含的一些字符,或者从头开始构建自己的字符集.

例如,如果你看一下Alamofire的参数编码,他们采取URLQueryAllowedCharacterSet然后删除generalDelimitersToEncode(包括文字#,[,],和@,但由于在一些旧的web服务器一个历史错误,既不?也没有/)和subDelimitersToEncode(即!,$,&,',(,),*,+,,,;,和=).这是正确的实现(虽然你可以辩论删除?和/),虽然相当复杂.也许CFURLCreateStringByAddingPercentEscapes更直接/更有效率.

Answer 4

 NSURL *url= [NSURL URLWithString:@"https://www.paypal.com/cgi-bin/webscr"];
 NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:aUrl
                                                        cachePolicy:NSURLRequestUseProtocolCachePolicy
                                                    timeoutInterval:10.0];
[request setHTTPMethod:@"POST"];
 NSString *postString = @"userId=2323";
[request setHTTPBody:[postString dataUsingEncoding:NSUTF8StringEncoding]];

Answer 5

上面的示例代码对我来说真的很有帮助(但正如上面已经暗示的那样),我认为你需要使用NSMutableURLRequest而不是NSURLRequest.目前的形式,我无法回应这个setHTTPMethod电话.改变类型固定的东西.