使用Python从字典中组合列表值的组合

Question

我有以下传入价值:

variants = {
  "debug" : ["on", "off"],
  "locale" : ["de_DE", "en_US", "fr_FR"],
  ...
}

我想处理它们,所以我得到以下结果:

combinations = [
  [{"debug":"on"},{"locale":"de_DE"}],
  [{"debug":"on"},{"locale":"en_US"}],
  [{"debug":"on"},{"locale":"fr_FR"}],
  [{"debug":"off"},{"locale":"de_DE"}],
  [{"debug":"off"},{"locale":"en_US"}],
  [{"debug":"off"},{"locale":"fr_FR"}]
]

这应该适用于字典中任意长度的键.在Python中使用itertools,但没有找到符合这些要求的任何内容.

Answer 1

import itertools as it

varNames = sorted(variants)
combinations = [dict(zip(varNames, prod)) for prod in it.product(*(variants[varName] for varName in varNames))]

嗯,这回来了:

[{'debug': 'on', 'locale': 'de_DE'},
 {'debug': 'on', 'locale': 'en_US'},
 {'debug': 'on', 'locale': 'fr_FR'},
 {'debug': 'off', 'locale': 'de_DE'},
 {'debug': 'off', 'locale': 'en_US'},
 {'debug': 'off', 'locale': 'fr_FR'}]

这可能不完全是你想要的.让我改编一下......

combinations = [ [ {varName: val} for varName, val in zip(varNames, prod) ] for prod in it.product(*(variants[varName] for varName in varNames))]

现在返回:

[[{'debug': 'on'}, {'locale': 'de_DE'}],
 [{'debug': 'on'}, {'locale': 'en_US'}],
 [{'debug': 'on'}, {'locale': 'fr_FR'}],
 [{'debug': 'off'}, {'locale': 'de_DE'}],
 [{'debug': 'off'}, {'locale': 'en_US'}],
 [{'debug': 'off'}, {'locale': 'fr_FR'}]]

Voilà;-)

Answer 2

combinations = [[{key: value} for (key, value) in zip(variants, values)] 
                for values in itertools.product(*variants.values())]

[[{'debug': 'on'}, {'locale': 'de_DE'}],
 [{'debug': 'on'}, {'locale': 'en_US'}],
 [{'debug': 'on'}, {'locale': 'fr_FR'}],
 [{'debug': 'off'}, {'locale': 'de_DE'}],
 [{'debug': 'off'}, {'locale': 'en_US'}],
 [{'debug': 'off'}, {'locale': 'fr_FR'}]]