And*_*rei 7 module commonjs node.js express typescript
在Node项目中使用Express和Typescript,这将是express.Router的"最佳实践".
示例目录结构
|directory_name
---server.js
|--node_modules
|--routes
---index.ts
|--admin
---admin.ts
|--products
---products.ts
|--authentication
---authentication.ts
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所以在index.ts里面它会封装和管理所有的子路由器
//admin.ts (nested inside of index.ts)
import * as express from "express";
export = (() => {
let router = express.Router();
router.get('/admin', (req, res) => {
res.json({success: true});
});
return router;
})();
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//index.ts (master file for express.Router)
import * as express from "express";
//import sub-routers
import * as adminRouter from "./admin/admin";
import * as productRouter from "./products/products";
export = (() => {
let router = express.Router();
// mount express paths, any addition middleware can be added as well.
// ex. router.use('/pathway', middleware_function, sub-router);
router.use('/products', productRouter);
router.use('/admin', adminRouter);
//return for revealing module pattern
return router;
})(); //<--- this is where I don't understand something....
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最后我们将设置我们的server.js
//the usual node setup
//import * as *** http, body-parser, morgan, mongoose, express <-- psudocode
import * as masterRouter from './routes/index'
var app = express();
//set-up all app.use()
app.use('/api', masterRouter);
http.createServer(app).listen(8080, () => {
console.log('listening on port 8080')
};
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我的主要问题是index.ts(masterRouter文件)和它是IIFe的嵌套路由
export =(function(){})();
应该是为路由器编写打字稿模块的正确/最佳方法吗?
或者使用另一种模式会更好,也许是利用模式的模式
export function fnName(){} - export class cName {} - export default.
IIFe的原因是当我将它们导入另一个文件时,我不需要初始化模块,每种类型的路由器只会有1个实例.
当json包含没有键的数组时,如何检查swiftyJSON中是否存在键
我知道swiftyJSON方法exists()但它似乎并不总是如他们所说.在下面这种情况下如何获得正确的结果?我无法更改JSON结构,因为我通过客户端的API获取此信息.
|directory_name
---server.js
|--node_modules
|--routes
---index.ts
|--admin
---admin.ts
|--products
---products.ts
|--authentication
---authentication.ts
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输出:
//admin.ts (nested inside of index.ts)
import * as express from "express";
export = (() => {
let router = express.Router();
router.get('/admin', (req, res) => {
res.json({success: true});
});
return router;
})();
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不应该打印,因为someKey不存在.但有时候这个密钥来自客户端的API,我需要找出它是否存在.
bas*_*rat
16
回答
在NodeJS中,每个文件都是一个模块.声明变量不会污染全局命名空间.所以你不需要使用好的老IIFE技巧来适当地限制变量(并防止全局污染/碰撞).
你会写:
import * as express from "express";
// import sub-routers
import * as adminRouter from "./admin/admin";
import * as productRouter from "./products/products";
let router = express.Router();
// mount express paths, any addition middleware can be added as well.
// ex. router.use('/pathway', middleware_function, sub-router);
router.use('/products', productRouter);
router.use('/admin', adminRouter);
// Export the router
export = router;
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更多关于模块
https://basarat.gitbooks.io/typescript/content/docs/project/modules.html
我的反应
我的主要问题是,index.ts(masterRouter文件)和IIFe的嵌套路由export = (function(){})();应该是为路由器编写typescript模块的正确/最佳方式
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