将矢量/数组从非托管C++传递到C#

Question

我想从非托管C++传递大约100 - 10,000点到C#.

C++端看起来像这样:

__declspec(dllexport) void detect_targets( char * , int  , /* More arguments */ )
{
    std::vector<double> id_x_y_z;
    // Now what's the best way to pass this vector to C#
}

现在我的C#端看起来像这样:

using System;
using System.Runtime.InteropServices;

class HelloCpp
{

    [DllImport("detector.dll")]

    public static unsafe extern void detect_targets( string fn , /* More arguments */ );

    static void Main()
    {
        detect_targets("test.png" , /* More arguments */ );
    }
}

我如何改变我的代码,以便将std :: vector从非托管C++传递给C#？

Answer 1

只要托管代码没有调整向量的大小,就可以访问缓冲区并将其作为指针传递给vector.data()(对于C++ 0x)或&vector[0].这导致零拷贝系统.

示例C++ API:

#define EXPORT extern "C" __declspec(dllexport)

typedef intptr_t ItemListHandle;

EXPORT bool GenerateItems(ItemListHandle* hItems, double** itemsFound, int* itemCount)
{
    auto items = new std::vector<double>();
    for (int i = 0; i < 500; i++)
    {
        items->push_back((double)i);
    }

    *hItems = reinterpret_cast<ItemListHandle>(items);
    *itemsFound = items->data();
    *itemCount = items->size();

    return true;
}

EXPORT bool ReleaseItems(ItemListHandle hItems)
{
    auto items = reinterpret_cast<std::vector<double>*>(hItems);
    delete items;

    return true;
}

呼叫者:

static unsafe void Main()
{
    double* items;
    int itemsCount;
    using (GenerateItemsWrapper(out items, out itemsCount))
    {
        double sum = 0;
        for (int i = 0; i < itemsCount; i++)
        {
            sum += items[i];
        }
        Console.WriteLine("Average is: {0}", sum / itemsCount);
    }

    Console.ReadLine();
}

#region wrapper

[DllImport("Win32Project1", ExactSpelling = true, CallingConvention = CallingConvention.Cdecl)]
static unsafe extern bool GenerateItems(out ItemsSafeHandle itemsHandle,
    out double* items, out int itemCount);

[DllImport("Win32Project1", ExactSpelling = true, CallingConvention = CallingConvention.Cdecl)]
static unsafe extern bool ReleaseItems(IntPtr itemsHandle);

static unsafe ItemsSafeHandle GenerateItemsWrapper(out double* items, out int itemsCount)
{
    ItemsSafeHandle itemsHandle;
    if (!GenerateItems(out itemsHandle, out items, out itemsCount))
    {
        throw new InvalidOperationException();
    }
    return itemsHandle;
}

class ItemsSafeHandle : SafeHandleZeroOrMinusOneIsInvalid
{
    public ItemsSafeHandle()
        : base(true)
    {
    }

    protected override bool ReleaseHandle()
    {
        return ReleaseItems(handle);
    }
}

#endregion

Answer 2

我使用C++ CLI包装器实现了这一点.C++ CLI是C++ C#interop的三种可能方法之一.另外两种方法是P/Invoke和COM.(我见过一些好人建议使用C++ CLI而不是其他方法)

为了将信息从本机代码编组到托管代码,您需要首先将本机代码包装在C++ CLI托管类中.创建一个新项目以包含本机代码及其C++ CLI包装器.确保/clr为此项目启用编译器开关.将此项目构建到dll.要使用此库,只需在C#中添加其引用并对其进行调用.如果两个项目都在同一个解决方案中,您可以执行此操作.

以下是我的源文件,用于将std::vector<double>本机代码编组为C#托管代码的简单程序.

1)Project EntityLib(C++ CLI dll)(带有包装器的本机代码)

文件NativeEntity.h

#pragma once

#include <vector>
class NativeEntity {
private:
    std::vector<double> myVec;
public:
    NativeEntity();
    std::vector<double> GetVec() { return myVec; }
};

文件NativeEntity.cpp

#include "stdafx.h"
#include "NativeEntity.h"

NativeEntity::NativeEntity() {
    myVec = { 33.654, 44.654, 55.654 , 121.54, 1234.453}; // Populate vector your way
}

File ManagedEntity.h (包装类)

#pragma once

#include "NativeEntity.h"
#include <vector>
namespace EntityLibrary {
    using namespace System;

    public ref class ManagedEntity {
    public:
        ManagedEntity();
        ~ManagedEntity();

        array<double> ^GetVec();
    private:
        NativeEntity* nativeObj; // Our native object is thus being wrapped
    };

}

File ManagedEntity.cpp

#include "stdafx.h"
#include "ManagedEntity.h"

using namespace EntityLibrary;
using namespace System;


ManagedEntity::ManagedEntity() {
    nativeObj = new NativeEntity();
}

ManagedEntity::~ManagedEntity() {
    delete nativeObj;

}

array<double>^ ManagedEntity::GetVec()
{
    std::vector<double> tempVec = nativeObj->GetVec();
    const int SIZE = tempVec.size();
    array<double> ^tempArr = gcnew array<double> (SIZE);
    for (int i = 0; i < SIZE; i++)
    {
        tempArr[i] = tempVec[i];
    }
    return tempArr;
}

2)Project SimpleClient(C#exe)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using EntityLibrary;

namespace SimpleClient {

    class Program {
        static void Main(string[] args) {
            var entity = new ManagedEntity();
            for (int i = 0; i < entity.GetVec().Length; i++ )
                Console.WriteLine(entity.GetVec()[i]);
        }
    }
}

Answer 3

我可以想到多个选项,但所有选项都包括复制数组的数据.使用[out]参数,您可以尝试:

C++代码

__declspec(dllexport) void __stdcall detect_targets(wchar_t * fn, double **data, long* len)
{
    std::vector<double> id_x_y_z = { 1, 2, 3 };

    *len = id_x_y_z.size();
    auto size = (*len)*sizeof(double);

    *data = static_cast<double*>(CoTaskMemAlloc(size));
    memcpy(*data, id_x_y_z.data(), size);
}

C#代码

[DllImport("detector.dll")]
public static extern void detect_targets(
    string fn, 
    [MarshalAs(UnmanagedType.LPArray, SizeParamIndex = 2)] out double[] points, 
    out int count);

static void Main()
{
    int len;
    double[] points;

    detect_targets("test.png", out points, out len);
}