无法在Spring Webservice中的START_ARRAY标记中反序列化对象的实例

Question

我目前无法连接到Android上的web服务.我使用jackson-core/databind/annotation-2.2.4和Spring RESTWebService.如果我从浏览器访问URL,我可以看到JSON响应:(服务器返回List\Shop \看起来像:)

[{"name":"shopqwe","mobiles":[],"address":{"town":"city",
"street":"streetqwe","streetNumber":"59","cordX":2.229997,"cordY":1.002539},
"shoe" [{"shoeName":"addidas","number":"631744030","producent":"nike","price":999.0,
"sizes":[30.0,35.0,38.0]}]

从客户端端点(Android应用程序)我收到此错误消息:

08-26 17:43:07.406: E/AllShopsAsyc(28203): Could not read JSON: Can not deserialize
instance of com.auginzynier.data.ShopContainer out of START_ARRAY token
08-26 17:43:07.406: E/AllShopsAsyc(28203):  at [Source:
com.android.okhttp.internal.http.HttpTransport$ChunkedInputStream@41efbd48; line: 1,
column: 1]; nested exception is com.fasterxml.jackson.databind.JsonMappingException:
Can not deserialize instance of com.auginzynier.data.ShopContainer out of START_ARRAY
token
08-26 17:43:07.406: E/AllShopsAsyc(28203):  at [Source:
com.android.okhttp.internal.http.HttpTransport$ChunkedInputStream@41efbd48; line: 1,
column: 1] 
08-26 17:43:07.406: E/AllShopsAsyc(28203):
org.springframework.http.converter.HttpMessageNotReadableException: Could not read
JSON: Can not deserialize instance of com.auginzynier.data.ShopContainer out of
START_ARRAY token

我的服务器请求

RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
ShopContainer response  = restTemplate.getForObject(url, ShopContainer.class);

ShopContainer的位置是:

public class ShopContainer {
   private List<Shop> shops;

商店,地址和鞋子的结构是:(我省略了getter和setter):

public class Shop {
@JsonProperty("name")    private String name;
@JsonProperty("mobiles")   private List<String> mobiles = new ArrayList<String>();
@JsonProperty("address")   private Address address;
@JsonProperty("shoe") private List<Shoe> shoe = new ArrayList<Shoe>();

public class Address {
@JsonProperty("town") private String town;
@JsonProperty("street") private String street;
@JsonProperty("streetNumber") private String streetNumber;
@JsonProperty("cordX") private Double cordX;
@JsonProperty("cordY") private Double cordY;

public class Shoe {
@JsonProperty("shoeName") private String shoeName;
@JsonProperty("number") private String number;
@JsonProperty("producent") private String producent;
@JsonProperty("price") private Double price;
@JsonProperty("sizes") private List<Double> sizes = new ArrayList<Double>();

我看这里和谷歌,但仍然无法弄清楚我在这一点上缺少什么.

任何回应都会非常有帮助.

问候.

@UPDATE

我使用jackson的ObjectMapper和RequestMethod.GET修复了JSON.它现在返回一个String.

list is List<Shop>

ObjectMapper mapper = new ObjectMapper();
mapper.writeValue(new File("D:\\Android\\shop.json"), list);
System.out.println(mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list));
return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list);

控制台中的JSON如下所示:

[ {
  "name" : "shopqwe",
  "mobiles" : [ ],
  "address" : {
    "town" : "city",
    "street" : "streetqwe",
    "streetNumber" : "59",
    "cordX" : 2.229997,
    "cordY" : 2.002539
  },
  "shoe" : [ {
    "shoeName" : "addidas",
    "number" : "631744033",
    "producent" : "nike",
    "price" : 10.0,
    "sizes" : [ 30.0, 35.0, 38.0 ]
  } ]
} ]

请求仍然不起作用 - 错误是相同的.

Answer 1

你的json包含一个数组,但你试图将它解析为一个对象.发生此错误是因为对象必须以{.

你有2个选择:

1. 你可以摆脱这个ShopContainer类而Shop[]不是使用它

   ShopContainer response  = restTemplate.getForObject(
       url, ShopContainer.class);
   

   用...来代替

   Shop[] response  = restTemplate.getForObject(url, Shop[].class);
   

   然后从中制作所需的物体.

2. 您可以更改服务器以返回对象而不是列表

   return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(list);
   

   用...来代替

   return mapper.writerWithDefaultPrettyPrinter().writeValueAsString(
       new ShopContainer(list));