我遇到了两个似乎有相同结果的查询:在分区上应用聚合函数.
我想知道这两个查询之间是否有任何区别:
SELECT empno,
deptno,
sal,
MIN(sal) OVER (PARTITION BY deptno) "Lowest",
MAX(sal) OVER (PARTITION BY deptno) "Highest"
FROM empl
SELECT empno,
deptno,
sal,
MIN(sal) KEEP (DENSE_RANK FIRST ORDER BY sal) OVER (PARTITION BY deptno) "Lowest",
MAX(sal) KEEP (DENSE_RANK LAST ORDER BY sal) OVER (PARTITION BY deptno) "Highest"
FROM empl
Run Code Online (Sandbox Code Playgroud)
第一个版本更合乎逻辑,但第二个版本可能是某种特殊情况,也许是一些性能优化.
MT0*_*MT0 26
MIN(sal) KEEP (DENSE_RANK FIRST ORDER BY sal) OVER (PARTITION BY deptno)
Run Code Online (Sandbox Code Playgroud)
该声明可以(大致)从右到左的顺序来考虑:
OVER (PARTITION BY deptno)意味着将行分成不同的组deptno; 然后ORDER BY sal表示对于每个分区,按行排序sal(隐式使用ASC结束顺序); 然后KEEP (DENSE_RANK FIRST表示为每个分区的有序行提供(连续)排名(对于排序列具有相同值的行将被赋予相同的排名)并丢弃所有未排在第一位的行; 最后MIN(sal) 对于每个分区的剩余行,返回最低工资.在这种情况下,MIN并且DENSE_RANK FIRST都在sal列上操作,因此将执行相同的操作并且KEEP (DENSE_RANK FIRST ORDER BY sal)是多余的.
但是,如果您使用不同的列作为最小值,那么您可以看到效果:
Oracle 11g R2架构设置:
CREATE TABLE test (name, sal, deptno) AS
SELECT 'a', 1, 1 FROM DUAL
UNION ALL SELECT 'b', 1, 1 FROM DUAL
UNION ALL SELECT 'c', 1, 1 FROM DUAL
UNION ALL SELECT 'd', 2, 1 FROM DUAL
UNION ALL SELECT 'e', 3, 1 FROM DUAL
UNION ALL SELECT 'f', 3, 1 FROM DUAL
UNION ALL SELECT 'g', 4, 2 FROM DUAL
UNION ALL SELECT 'h', 4, 2 FROM DUAL
UNION ALL SELECT 'i', 5, 2 FROM DUAL
UNION ALL SELECT 'j', 5, 2 FROM DUAL;
Run Code Online (Sandbox Code Playgroud)
查询1:
SELECT DISTINCT
MIN(sal) KEEP (DENSE_RANK FIRST ORDER BY sal) OVER (PARTITION BY deptno) AS min_sal_first_sal,
MAX(sal) KEEP (DENSE_RANK FIRST ORDER BY sal) OVER (PARTITION BY deptno) AS max_sal_first_sal,
MIN(name) KEEP (DENSE_RANK FIRST ORDER BY sal) OVER (PARTITION BY deptno) AS min_name_first_sal,
MAX(name) KEEP (DENSE_RANK FIRST ORDER BY sal) OVER (PARTITION BY deptno) AS max_name_first_sal,
MIN(name) KEEP (DENSE_RANK LAST ORDER BY sal) OVER (PARTITION BY deptno) AS min_name_last_sal,
MAX(name) KEEP (DENSE_RANK LAST ORDER BY sal) OVER (PARTITION BY deptno) AS max_name_last_sal,
deptno
FROM test
Run Code Online (Sandbox Code Playgroud)
结果:
| MIN_SAL_FIRST_SAL | MAX_SAL_FIRST_SAL | MIN_NAME_FIRST_SAL | MAX_NAME_FIRST_SAL | MIN_NAME_LAST_SAL | MAX_NAME_LAST_SAL | DEPTNO |
|-------------------|-------------------|--------------------|--------------------|-------------------|-------------------|--------|
| 1 | 1 | a | c | e | f | 1 |
| 4 | 4 | g | h | i | j | 2 |
Run Code Online (Sandbox Code Playgroud)
在您的示例中,没有什么区别,因为您的汇总位于您正在排序的同一列上。“ KEEP”的真正点/功效是当您在不同的列上进行汇总和排序时。例如(从其他答案中借用“测试”表)...
SELECT deptno, min(name) keep ( dense_rank first order by sal desc, name ) ,
max(sal)
FROM test
group by deptno
Run Code Online (Sandbox Code Playgroud)
;
该查询获取每个部门中薪水最高的人员的姓名。考虑不带“ KEEP”子句的替代项:
SELECT deptno, name, sal
FROM test t
WHERE not exists ( SELECT 'person with higher salary in same department'
FROM test t2
WHERE t2.deptno = t.deptno
and (( t2.sal > t.sal )
OR ( t2.sal = t.sal AND t2.name < t.name ) ) )
Run Code Online (Sandbox Code Playgroud)
KEEP子句更简单,更高效(在这个简单的示例中,只有3个一致的获取与34个一致的获取)。
| 归档时间: |
|
| 查看次数: |
33156 次 |
| 最近记录: |