Python - 使用列表推导查找增量编号序列

Question

我在列表中有一系列数字,我正在寻找一个优雅的解决方案,最好是列表理解,以获得单个序列(包括单个值).我已经解决了这个小问题,但它并不是非常pythonic.

以下列表定义了输入序列:

input = [1, 2, 3, 4, 8, 10, 11, 12, 17]

期望的输出应该是:

output = [
  [1, 2, 3, 4],
  [8],
  [10, 11, 12],
  [17],
]

Answer 1

>>> from itertools import groupby, count
>>> nums = [1, 2, 3, 4, 8, 10, 11, 12, 17]
>>> [list(g) for k, g in groupby(nums, key=lambda n, c=count(): n - next(c))]
[[1, 2, 3, 4], [8], [10, 11, 12], [17]]

Answer 2

Pythonic意味着简单,直接的代码,而不是单行代码.

def runs(seq):
    result = []
    for s in seq:
        if not result or s != result[-1][-1] + 1:
            # Start a new run if we can't continue the previous one.
            result.append([])
        result[-1].append(s)
    return result

print runs([1, 2, 3, 4, 8, 10, 11, 12, 17])