如何使用Lambda表达式编写此linq查询
public List<Employee> GetList()
{
return (from c in DALContext.MST
select new Employee(ID=c.CD, Name=c.NAME)).ToList();
}
Run Code Online (Sandbox Code Playgroud) 我试图在同一个表中插入2行.第一个将从select输入数据,第二个将使用vars作为数据.我能够插入第一行但无法插入多行.
$ partner_id用于将行相互链接.为此我在php中使用生成的32char值.无论如何将edit_partner_id设置为mysql作为插入的第一行的id,或者这是不可能的,因为必须先创建第一行才能获得最后一个id?
是否有可能还添加更新或我是否必须在单独的查询中运行此更新?
$sql = "INSERT INTO edits_customers (customer_id, creator_id, firstname, surname,
house_no, address_1, address_2, address_3, city, county, postcode,
country, email, home_tel, mobile_tel, work_tel, notes, edit_type,
edit_partner_id )
(SELECT *, 'before', '{$partner_id}' FROM customers WHERE customers.id = 123),
('{$var1}', '{$var2}', '', '', '', '', '', '', '', '', '', '', '', '', '', '',
'', 'after', $partner_id)";
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谢谢
我想知道如何检测我对UIButton的长按?我听说过UILongPressGestureRecognizer但我完全不确定如何使用它.
我成功地将我的plist数组和字典加载到我的表中.我想在练习的详细视图中将exerciseName值设置为UILabel.
<array>
<dict>
<key>exercises</key>
<array>
<dict>
<key>exerciseDetail</key>
<string></string>
<key>exerciseName</key>
<string>Ab Crunch Machine</string>
</dict>
<dict>
<key>exerciseDetail</key>
<string></string>
<key>exerciseName</key>
<string>Ab Roller</string>
</dict>
</array>
<key>muscleName</key>
<string>Abdominals</string>
</dict>
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练习细节现在是空白的,但最终会在相同练习的详细视图中加载UILabel或UITextView.
我猜我需要做一些事情
label.text =[[self.exerciseArray objectAtIndex:indexPath.row]objectForKey:@"exercises"];
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编辑:
对于我的exerciseViewController didSelectIndexAtRow我有:
NSUserDefaults *def = [NSUserDefaults standardUserDefaults];
[def setObject:exerciseArray forKey:@"exercises"];
[def setValue:[NSString stringWithFormat:@"%d",indexPath.row] forKey:@"exercises"];
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对于detailViewController的ViewDidLoad,我有:viewDidLoad for exerciseDetailView
self.navigationItem.title = @"Exercise Detail";
NSMutableArray *exerciseDetailArray = [[[NSUserDefaults alloc] objectForKey:@"exercises"] mutableCopy];
int indexValue = [[[NSUserDefaults alloc] valueForKey:@"exercises"] intValue];
name.text =[[exerciseDetailArray objectAtIndex:indexValue] objectForKey:@"exerciseName"];
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控制台输出:
2011-03-19 22:52:08.279 Curl[32300:207] exercisedetalarray: (
{
exerciseDetail = "";
exerciseName …Run Code Online (Sandbox Code Playgroud) 如何在JavaScript中将转换'1'转换为'0001'而不使用任何第三方库.我使用spritf在php中完成了这个:$time = sprintf('%04.0f',$time_arr[$i]);
我为2名玩家制作了一个Tic-Tac-Toe游戏.现在,我想给游戏人工智能.
这样的游戏可以在1个玩家和计算机之间播放.
请帮助我该如何开始?
我正在寻找一种方法,使--insecure选项成为任何hg\ TortoiseHg命令的默认选项.
请不要写这是一个不好的做法 - 我知道可能的风险并认为它们是完全可以接受的.
Xcode4放弃了PPC支持,所以当我尝试构建PIL时,它会引发仇恨:
Bens-MacBook-Air:Imaging-1.1.7 bkeating$ python setup.py build
running buildrunning build_pyrunning build_ext
--- using frameworks at /System/Library/Frameworks
building '_imaging' extension
/usr/bin/gcc-4.0 -fno-strict-aliasing -fno-common -dynamic -DNDEBUG -g -fwrapv -Os -Wall -Wstrict-prototypes -DENABLE_DTRACE -arch i386 -arch ppc -arch x86_64 -pipe -DHAVE_LIBJPEG -DHAVE_LIBZ -I/System/Library/Frameworks/Tcl.framework/Headers -I/System/Library/Frameworks/Tk.framework/Headers -I/usr/local/include/freetype2 -IlibImaging -I/System/Library/Frameworks/Python.framework/Versions/2.6/include -I/usr/local/include -I/usr/include -I/System/Library/Frameworks/Python.framework/Versions/2.6/include/python2.6 -c decode.c -o build/temp.macosx-10.6-universal-2.6/decode.o
/usr/libexec/gcc/powerpc-apple-darwin10/4.2.1/as: assembler (/usr/bin/../libexec/gcc/darwin/ppc/as or /usr/bin/../local/libexec/gcc/darwin/ppc/as) for architecture ppc not installed
Installed assemblers are:
/usr/bin/../libexec/gcc/darwin/x86_64/as for architecture x86_64
/usr/bin/../libexec/gcc/darwin/i386/as for architecture i386
decode.c:688: fatal error: error writing to -: Broken pipe …Run Code Online (Sandbox Code Playgroud) 在不暴露外键的情况下执行一对多关系的删除时,EF会删除父记录并尝试使子记录上的外键为空.这当然会导致错误,因为外键不可为空.将外键添加到子类会覆盖此行为,但我宁愿不公开它.
例如,给定以下两个类,我不希望将JobId作为Project类的属性.
public class Job : ModelBase
{
[Required]
[StringLength(100)]
public string Company { get; set; }
[Required]
[StringLength(100)]
public string JobTitle { get; set; }
public ICollection<Project> Projects { get; set; }
}
public class Project : ModelBase
{
[Required]
[StringLength(100)]
public string Name { get; set; }
[Required]
public string Summary { get; set; }
public int JobId { get; set; }
}
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有没有办法在EF Code First中启用级联删除而不在关系的多方面暴露外键?
想象一下,我运行这个:
$.ajax({
type: 'POST',
url: '/ajax/watch.php',
data: {'watch':'aukcia', 'id':aukciaID},
complete: function(responseText){
alert(responseText);
}
});
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在/ajax/watch.php里面,假设我有这个:
echo 'this is what I want';
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并且警报(responseText)返回:
[object Object]
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而不是我需要的文本字符串.有什么帮助吗?
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