我正在关注最新的2011年2月Azure培训套件示例.
我已成功部署使用
New-Deployment -serviceName xxxxmytodo99
-subscriptionId cxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx
-certificate (get-item cert:\CurrentUser\MY\xxxxxxxxxxxx)
-slot staging
-package MyTodo.cspkg
-configuration ServiceConfiguration.cscfg
-label "v2.0"
-storageServiceName xxxxmytodo99
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然后运行下一步 -
Get-HostedService -serviceName xxxxmytodo99
-subscriptionId cxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx
-certificate (get-item cert:\CurrentUser\MY\xxxxxxxxxxxx)
| Get-Deployment staging
| Set-Deployment -package MyTodo.cspkg
-configuration ServiceConfiguration.cscfg
-label "v2.1"
| Get-OperationStatus -WaitToComplete
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给出了这个错误.
Set-Deployment : The remote server returned an unexpected response: (400) Bad Request.
At line:1 char:232
+ Get-HostedService -serviceName xxxxmytodo99 -subscriptionId cxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx -certificate (get-item cert:\CurrentUser\MY\xxxxxxxxxxxx) | Get-Deployment staging | Set-Deployment <<<< -package MyTodo.cspkg -configuration ServiceConfiguration.cscfg -label …Run Code Online (Sandbox Code Playgroud) 如何告诉EF如何命名数据库以及将其放在何处?
如果Web.Config中没有连接字符串,它会尝试将其放在本地SQLEXPRESS服务器中,但我想将它放在已知的SQL Server上,并将其命名为我想要的.有什么建议?
下面的示例代码是John Resig的Learning Advnaced JavaScript中的#36.http://ejohn.org/apps/learn/#36
It is called We need to make sure the new operator is always used.
六个问题 - 我希望尽可能多地提供详细信息
1)function User在这段代码中实际调用过吗?我注意到,当它说assert(user...),用户是小写.如果函数被调用,怎么样?它在断言变量user时会被调用,变量user附加了一个函数调用,即User("John," name)
2)如果我m correct in assuming that function User is never called, is there a way that the codethis.name = first +""+ last;`运行?
3)如果调用函数User,或者如果要调用它,可以解释函数User内的操作顺序.例如,this.name = first + " " + last;如果调用此函数或调用此函数,它会在返回之前返回新用户吗?
4)!(this instanceof User)如果是真的,以什么方式.由于函数User是对象,不会"这个"总是它自己的一个实例吗?
5)关于第一个断言,即assert(user, "this was defined correctly, even if it was by mistake") …
我创建的这个IntentService将在onStartCommand()和onDestroy()中显示Toasts,但不在onHandleIntent()中显示.我错过了一些关于IntentService限制的内容吗?
public class MyService extends IntentService {
private static final String TAG = "MyService";
public MyService(){
super("MyService");
}
@Override
protected void onHandleIntent(Intent intent) {
cycle();
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
Toast.makeText(this, "service starting", Toast.LENGTH_SHORT).show(); //This happens!
return super.onStartCommand(intent,flags,startId);
}
@Override
public void onCreate() {
super.onCreate();
}
@Override
public void onDestroy() {
Toast.makeText(this, "service stopping", Toast.LENGTH_SHORT).show(); //This happens!
super.onDestroy();
}
private void cycle(){
Toast.makeText(this, "cycle done", Toast.LENGTH_SHORT).show(); //This DOESN'T happen!
Log.d(TAG,"cycle completed"); //This happens!
} …Run Code Online (Sandbox Code Playgroud) 我正在尝试发布项目(工具vs2010),但不能一直得到下面的错误.我从另一个项目粘贴到我的项目文件,然后我将命名空间(OldProjectName)更改为父项目(NewProjectName).但它仍然从某个地方获取有关旧项目的信息.
我清理了溶液,建造,重建.关闭并重新打开并始终出现相同的错误.
我能够构建项目但是发布它.
什么可以导致问题的想法?
错误1将文件obj\Debug\OldProjectName.csproj.FileListAbsolute.txt复制到obj\Debug\Package\PackageTmp\_ obj\Debug\OldProjectName.csproj.FileListAbsolute.txt失败.找不到文件'obj\Debug\OldProjectName.csproj.FileListAbsolute.txt'.0 0 NewProjectName
我似乎记得当表中的一行更新时,SQL Server首先删除该行,然后重新添加该行,如果存在这样的列,则具有相同的列标识值.谁能证实这一点?
例如,我有一个无序的值列表[10,20,50,200,100,300,250,150]
我有这个代码,它返回下一个更大的值:
def GetNextHighTemp(self, temp, templist):
target = int(temp)
list = []
for t in templist:
if t != "":
list.append(int(t))
return str(min((abs(target - i), i) for i in list)[1])
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例如,如果temp = 55,它将返回'100'.
但是我怎样才能获得较小的价值?那是如何让它返回'50'?
谢谢.
编辑 - 现在正在工作
def OnTWMatCurrentIndexChanged(self):
self.ClearTWSelectInputs()
material = self.cb_TW_mat.currentText()
temp = self.txt_design_temp.text()
if material != "":
Eref = self.GetMaterialData(material, "25", "elast")
if Eref and Eref != "":
Eref = str(float(Eref) / 1000000000)
self.txt_TW_Eref.setText(Eref)
else:
self.txt_TW_Eref.setText("194.8")
self.ShowMsg("No temperature match found for E<sub>ref</sub> in material data file. …Run Code Online (Sandbox Code Playgroud) 我无法让我的DropDownList将所选项目设置为模型中的值.
模型中的字段只是用户名称标题的字符串(Mr,Miss等..)以下是我的代码.
<td>
@{ var list = new List<SelectListItem>(new[] {
new SelectListItem{ Selected = string.IsNullOrEmpty(Model.Title), Text="",Value=""},
new SelectListItem{ Selected = Model.Title.Equals("Mr"), Text="Mr",Value="Mr"},
new SelectListItem{ Selected = Model.Title.Equals("Mrs"), Text="Mrs",Value="Mrs"},
new SelectListItem{ Selected = Model.Title.Equals("Miss"), Text="Miss",Value="Miss"},
new SelectListItem{Selected = Model.Title.Equals("Ms"), Text="Ms",Value="Ms"}
});
}
@Html.DropDownListFor(m=>m.Title, list)
</td>
Run Code Online (Sandbox Code Playgroud) 我正在尝试用MvcContrib来分页Html.Pager(),但我的剃刀视图无法引用正确的命名空间.
控制器还可以:
using MvcContrib.Pagination;
...
public ActionResult List(int? page)
{
return View(new UserRepository().GetUserList().AsPagination(page ?? 1, 10));
}
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但是,观点无法理解:
@using MvcContrib
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要么
@Html.Pager((IPagination)Model)
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我通过NuGet安装了MvcContrib.我尝试添加MvcContrib,MvcContrib.UI并MvcContrib.UI.Html命名空间<pages><namespaces>在web.config中没有运气.我错过了什么?
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