我有这个我想做的事情.我有一张地图的主要图片,在该地图中有区域.这些区域上有热点,因此您可以单击它们,它将仅用区域替换整个地图.(只是一个简单的div交换).
我需要它作为一个div因为在这里div我有热点列出.
总共有4个divs我需要这样做.
如果有人能帮助我那将是非常棒的!
因此,表中列出的链接需要单独替换图像div.
<tr class="thumb"></tr>
<td>All Regions (shows main map) (link)</td>
</tr>
<tr class="thumb"></tr>
<td>Northern Region (link)</td>
</tr>
<tr class="thumb"></tr>
<td>Southern Region (link)</td>
</tr>
<tr class="thumb"></tr>
<td>Eastern Region (link)</td>
</tr>
</table>
<div>All Regions image</div>
<div>northern image</div>
<div>southern image</div>
<div>Eastern image</div>
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我不允许发布图片,因为我没有足够的分数,所以我知道图片链接不起作用.
不确定这里发生了什么或我出错的地方但是与Chrome 9. IE8,Opera 11或Safari 5相比,FF3.6没有正确显示下面链接中的绿色按钮.
所有其他人把按钮放在父母的右下角,12px.FF3.6将它放在24px并且在右侧:
任何人都知道这个问题或者我错过了一些明显的东西?
更新:确认FF4 Beta 11中的问题.考虑提交Mozilla.
谢谢,丹尼斯
在Delphi中更新状态栏需要花费很长时间!
示例:我搜索文件并显示状态栏中找到和搜索的文件数:
OwnerForm.StatusBar1.SimpleText
:= Format('Searching (%d found in %d files) ...', [NumFound, Total]);
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对于每200次更新状态栏,搜索大约增加1秒的时间.
有没有办法减少这种过多的开销,但仍然更新用户的状态?
我试图让我的iOS 4地址簿的三个来源(1个MobileMe源和2个*ExchangeGAL源)的人.
NSLog语句总是为ExchangeGAL返回0个人,但返回MobileMe的人数.
通过使用ABAddressBookCopyArrayOfAllSources(addressBook)获取iOS通讯录中的所有源代码后,我尝试按源迭代源以获取每个源的更多信息.
我正确使用ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering吗?
期望在不同的地址簿来源中计算所有人.
-(void)countPeopleInSources
{
ABAddressBookRef addressBook = ABAddressBookCreate();
CFArrayRef allSources = ABAddressBookCopyArrayOfAllSources(addressBook);
for (CFIndex i = 0; i < CFArrayGetCount(allSources); i++)
{
ABRecordRef source = (ABRecordRef)CFArrayGetValueAtIndex(allSources, i);
NSNumber *sourceTypeRef = (NSNumber *)((CFNumberRef)ABRecordCopyValue(source, kABSourceTypeProperty));
ABPersonSortOrdering sortOrdering = ABPersonGetSortOrdering();
int sourceType = [sourceTypeRef intValue];
switch (sourceType) {
case kABSourceTypeCardDAV:
NSLog(@"SourceTypeCardDAV");
break;
case kABSourceTypeCardDAVSearch:
NSLog(@"SourceTypeCardDAVSearch");
break;
case kABSourceTypeExchange:
NSLog(@"SourceTypeExchange");
break;
case kABSourceTypeExchangeGAL:
NSLog(@"SourceTypeExchangeGAL");
break;
case kABSourceTypeLDAP:
NSLog(@"SourceTypeLDAP");
break;
case kABSourceTypeLocal:
NSLog(@"SourceTypeLocal");
break;
case kABSourceTypeMobileMe:
NSLog(@"SourceTypeMobileMe");
break;
default:
break;
} …Run Code Online (Sandbox Code Playgroud) 我正在开发一个使用OpenGL framebuffer/renderbuffer绘制写意线的项目.这个应用程序使用OpenGL ES 1.x,我无法弄清楚如何将当前屏幕转储到PNG或JPG图像.
感谢您阅读此问题.
来自OpenGL新手.
用于创建帧缓冲区和渲染缓冲区的代码.
// Generate IDs for a framebuffer object and a color renderbuffer
glGenFramebuffersOES(1, &viewFramebuffer);
glGenRenderbuffersOES(1, &viewRenderbuffer);
glBindFramebufferOES(GL_FRAMEBUFFER_OES, viewFramebuffer);
glBindRenderbufferOES(GL_RENDERBUFFER_OES, viewRenderbuffer);
// This call associates the storage for the current render buffer with the EAGLDrawable (our CAEAGLLayer)
// allowing us to draw into a buffer that will later be rendered to screen wherever the layer is (which corresponds with our view).
[context renderbufferStorage:GL_RENDERBUFFER_OES fromDrawable:(id<EAGLDrawable>)self.layer];
glFramebufferRenderbufferOES(GL_FRAMEBUFFER_OES, GL_COLOR_ATTACHMENT0_OES, GL_RENDERBUFFER_OES, viewRenderbuffer);
glGetRenderbufferParameterivOES(GL_RENDERBUFFER_OES, GL_RENDERBUFFER_WIDTH_OES, &backingWidth);
glGetRenderbufferParameterivOES(GL_RENDERBUFFER_OES, GL_RENDERBUFFER_HEIGHT_OES, &backingHeight);
// …Run Code Online (Sandbox Code Playgroud) SQL Server 2005数据库.我有许多记录的临时表,这些记录是从RSS源,需要周期性地插入.有些数据会改变,有些数据会保持不变.我只需要插入"新"的记录,并消除将导致重复记录的冗余数据的机会.我该如何做到这一点?
示例,tempTable,
BEGIN
INSERT INTO myTable
(
row1
,row2
,row3
)
SELECT
row1
,row2
,row3
FROM @tempTable
END
Run Code Online (Sandbox Code Playgroud) 我有一些像这样的代码,我想选择div中<a>的类的每个标签statusfoo
<div id="foo">
...
<a class = "status"> ... </a>
...
</div>
Run Code Online (Sandbox Code Playgroud) 我需要从我导入的csv的末尾删除一些冗余的'\n',然后再将它们分成一个数组(否则我得到额外的空行).
public function parseCSV(data:String):Array {
//something to strip linebreaks, \n and \r from end of array
var lines : Array = data.split ( /\R/ );
var preamble : Array = lines.splice(0,trashLength);
var keyArray : Array = lines.splice ( 0, 1 )[0].split ( "," );
var assocArray : Array = [];
for each (var line:String in lines)
{
var valArray : Array = line.split ( "," );
var assoc : Object = {};
for (var i : int = 0; i …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用Scala解析器组合器编写CSV解析器.语法基于RFC4180.我想出了以下代码.它几乎可以工作,但我不能让它正确地分隔不同的记录.我错过了什么?
object CSV extends RegexParsers {
def COMMA = ","
def DQUOTE = "\""
def DQUOTE2 = "\"\"" ^^ { case _ => "\"" }
def CR = "\r"
def LF = "\n"
def CRLF = "\r\n"
def TXT = "[^\",\r\n]".r
def file: Parser[List[List[String]]] = ((record~((CRLF~>record)*))<~(CRLF?)) ^^ {
case r~rs => r::rs
}
def record: Parser[List[String]] = (field~((COMMA~>field)*)) ^^ {
case f~fs => f::fs
}
def field: Parser[String] = escaped|nonescaped
def escaped: Parser[String] = (DQUOTE~>((TXT|COMMA|CR|LF|DQUOTE2)*)<~DQUOTE) ^^ { case …Run Code Online (Sandbox Code Playgroud) 我最近一直在考虑转换到Python编程语言.目前,Matlab是我部门快速开发和编写代码原型的首选语言.它非常擅长这一点,但是Mathworks(生产Matlab的公司)一直在修改许可条款,导致无法存在的麻烦.
iphone ×2
jquery ×2
cocoa-touch ×1
css ×1
csv ×1
delphi ×1
firefox ×1
forms ×1
html ×1
insert ×1
ios ×1
javascript ×1
matlab ×1
numpy ×1
objective-c ×1
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parsing ×1
performance ×1
python ×1
rendering ×1
scala ×1
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selector ×1
statusbar ×1
string ×1
swap ×1
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