问题列表 - 第46656页

如何解决延迟作业中的反序列化错误?

我正在尝试使用DelayedJob并且作业失败,在数据库中出现以下错误:

{Delayed::DeserializationError
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/serialization/active_record.rb:7:in `yaml_new'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/yaml.rb:133:in `transfer'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/yaml.rb:133:in `node_import'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/yaml.rb:133:in `load'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/yaml.rb:133:in `load'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/backend/base.rb:79:in `payload_object'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/backend/base.rb:87:in `invoke_job_without_newrelic_transaction_trace'
(eval):3:in `invoke_job'
/Library/Ruby/Gems/1.8/gems/newrelic_rpm-2.13.4/lib/new_relic/agent/instrumentation/controller_instrumentation.rb:252:in `perform_action_with_newrelic_trace'
/Library/Ruby/Gems/1.8/gems/newrelic_rpm-2.13.4/lib/new_relic/agent/method_tracer.rb:141:in `trace_execution_scoped'
/Library/Ruby/Gems/1.8/gems/newrelic_rpm-2.13.4/lib/new_relic/agent/instrumentation/controller_instrumentation.rb:247:in `perform_action_with_newrelic_trace'
(eval):2:in `invoke_job'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:120:in `run'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/timeout.rb:62:in `timeout'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:120:in `run'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/benchmark.rb:308:in `realtime'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:119:in `run'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:177:in `reserve_and_run_one_job'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:104:in `work_off'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:103:in `times'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:103:in `work_off'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:78:in `start'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/benchmark.rb:308:in `realtime'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:77:in `start'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:74:in `loop'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:74:in `start'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/tasks.rb:9
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:in `call'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:in `execute'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:in `each'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:in `execute'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:597:in `invoke_with_call_chain'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/monitor.rb:242:in `synchronize'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:590:in `invoke_with_call_chain'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:583:in `invoke'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2051:in `invoke_task'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `top_level'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `each'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `top_level'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:in …

ruby-on-rails delayed-job deserialization

35
推荐指数
2
解决办法
1万
查看次数

7
推荐指数
1
解决办法
1万
查看次数

wxpython菜单栏没有显示

我正在尝试使用wxpython为gui编写一个时间表程序,并且正在使用wxpython wiki上的入门教程来加快wxpython的速度,但是当我尝试向wxFrame添加菜单栏时,菜单栏没有显示.任何想法为什么会这样?我使用的是ubuntu 10.10和python 2.7.代码如下:

#! /usr/bin/env python2.7
import wx, os

class MainWindow(wx.Frame):
    def __init__(self, parent, title):
        wx.Frame.__init__(self, parent, title=title, size=(200,100))
        self.control = wx.TextCtrl(self, style=wx.TE_MULTILINE)
        self.CreateStatusBar() # A Statusbar in the bottom of the window


        # Creating the menubar.
        menuBar = wx.MenuBar()

         # Setting up the menu.
        filemenu= wx.Menu()

        # wx.ID_ABOUT and wx.ID_EXIT are standard ids provided by wxWidgets.
        menuAbout = filemenu.Append(wx.ID_ABOUT, "&About"," Information about this program")
        menuExit = filemenu.Append(wx.ID_EXIT,"E&xit"," Terminate the program")

        menuBar.Append(filemenu,"&File") # Adding the "filemenu" to the MenuBar …
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wxpython

3
推荐指数
1
解决办法
3748
查看次数

在python中合并连接两个生成器

我想通过密钥合并两个京都内阁 B 树数据库。(京都内阁python api)。结果列表应包含两个输入数据库中任何一个的每个唯一键(及其值)。

以下代码有效,但我认为它丑陋。
left_generator/right_generator 是两个游标对象。如果生成器耗尽, get() 返回 None 尤其奇怪。

def merge_join_kv(left_generator, right_generator):
stop = False
while left_generator.get() or right_generator.get():
    try:
        comparison = cmp(right_generator.get_key(), left_generator.get_key())
        if comparison == 0:
            yield left_generator.get_key(), left_generator.get_value()
            left_generator.next()
            right_generator.next()
        elif (comparison < 0) or (not left_generator.get() or not right_generator.get()):
            yield right_generator.get_key(), right_generator.get_value()
            right_generator.next()   
        else:
            yield left_generator.get_key(), left_generator.get_value()
            left_generator.next()    
    except StopIteration:
        if stop:
            raise
        stop = True
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通常:是否有一个函数/库将生成器与 cmp() 合并?

python generator

3
推荐指数
1
解决办法
2874
查看次数

将函数放在变量中的JavaScript优势?

我已经看到最近的代码示例将函数放在变量中,然后像普通函数一样调用函数.

如:

var myFunctionName = function() {
    Code Here...
}

myFunctionName();
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我相信更先进的场景有很多优点,但我只是好奇.

javascript variables function

9
推荐指数
2
解决办法
8065
查看次数

为MVC 3实现一点IOC

我正在设计一个允许我模拟我的数据库的设计,以便我可以测试我的观点.我不想阅读关于IOC的完整书籍,因为我现在没有时间.所以,这是我的家常菜.

控制器:

    public ActionResult Milestone()
    {
        var result = SJMServiceFactory.GetService("Milestone");
        return View(result);
    }
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厂:

public static class SJMServiceFactory
{
    public static DatabaseCollection_Result<T> GetService(string serviceName)
    {
        switch(serviceName)
        {
            case("Milestone"): return MileStoneService.GetMilestone();
            case ("MilestoneMock"): return MileStoneService.GetMilestone(true);
            default : return default(T);
        }
    }
}
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里程碑

public class MileStoneService
{
    public MileStoneService()
    {

    }
    public static DatabaseCollection_Result<Milestone> GetMilestone(bool Mock)
    {
        if (Mock)
        {
            DatabaseCollection_Result<Milestone> mileStones = new DatabaseCollection_Result<Milestone>();
            Milestone milestone1 = new Milestone();
            milestone1.Name = "New";
            Milestone milestone2 = new Milestone();
            milestone2.Name = "Assessment"; …
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c# inversion-of-control asp.net-mvc-3

3
推荐指数
2
解决办法
982
查看次数

我正在尝试写一个C#函数的奇怪问题

我正在写这个函数.

  const int ProgressBarLength = 230;
  foreach (TransactionDetail item in list)
  {
      var itemProgress =
        ((ProgressBarLength/item.PurchasesRequired) *
        Convert.ToInt32(item.TransactionAmount));

      item.ProgressBar = itemProgress > ProgressBarLength ? ProgressBarLength : itemProgress;
  }
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现在TransactionDetail我的循环中有2 秒.

如果item.PurchasesRequired = 500TransactionAmount = 199.0结果值为0.但是,如果item.PurchasesRequired = 5TransactionAmount = 94.0它返回有效结果.

我究竟做错了什么?

c#

0
推荐指数
1
解决办法
88
查看次数

MATLAB不会抛出OutOfMemoryExceptions或最大可变大小错误

在之前版本的MATLAB(7.6)中,我曾经得到过OutOfMemoryErrors,我觉得这有点烦人.但是自从我升级到7.11后,出于某种原因它不再抛出错误了.

这意味着当我意外地尝试使变量太大时,MATLAB shell将尝试创建变量并使我的机器停止运行.

我真的很想抛出这些错误,以便我可以优雅地退出或调试我的代码,但我无法在任何地方找到解决方案.

可能有用的细节:我在64位机器上使用OSX 10.5,具有4GB RAM.

在MATLAB 7.6中:

$ rand(50000);
??? Error using ==> rand
Maximum variable size allowed by the program is exceeded.
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在MATLAB 7.11中:

$ rand(50000);
(hang)
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matlab out-of-memory

7
推荐指数
1
解决办法
424
查看次数

如何验证是否在Rails中实际更新了update_all

鉴于此代码

def create
  @upgrades = User.update_all(["role = ?","upgraded"], :id => params[:upgrade])
  redirect_to admin_upgrades_path, :notice => "Successfully upgraded user."    
end
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如果保存或不重定向到适当的页面和消息,我如何在该操作中实际验证?

ruby ruby-on-rails ruby-on-rails-3

5
推荐指数
1
解决办法
6735
查看次数

如果我在其中加载带有(ns my-namespace)的文件,为什么不切换我当前的名称空间?

我有这样的文件

(ns boston.core)
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(load "boston/core")但是,如果我来自REPL,我*ns*不会改变boston但仍然存在user.为什么是这样?

clojure

5
推荐指数
1
解决办法
1492
查看次数