我正在尝试使用DelayedJob并且作业失败,在数据库中出现以下错误:
{Delayed::DeserializationError
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/serialization/active_record.rb:7:in `yaml_new'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/yaml.rb:133:in `transfer'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/yaml.rb:133:in `node_import'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/yaml.rb:133:in `load'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/yaml.rb:133:in `load'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/backend/base.rb:79:in `payload_object'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/backend/base.rb:87:in `invoke_job_without_newrelic_transaction_trace'
(eval):3:in `invoke_job'
/Library/Ruby/Gems/1.8/gems/newrelic_rpm-2.13.4/lib/new_relic/agent/instrumentation/controller_instrumentation.rb:252:in `perform_action_with_newrelic_trace'
/Library/Ruby/Gems/1.8/gems/newrelic_rpm-2.13.4/lib/new_relic/agent/method_tracer.rb:141:in `trace_execution_scoped'
/Library/Ruby/Gems/1.8/gems/newrelic_rpm-2.13.4/lib/new_relic/agent/instrumentation/controller_instrumentation.rb:247:in `perform_action_with_newrelic_trace'
(eval):2:in `invoke_job'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:120:in `run'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/timeout.rb:62:in `timeout'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:120:in `run'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/benchmark.rb:308:in `realtime'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:119:in `run'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:177:in `reserve_and_run_one_job'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:104:in `work_off'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:103:in `times'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:103:in `work_off'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:78:in `start'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/benchmark.rb:308:in `realtime'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:77:in `start'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:74:in `loop'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/worker.rb:74:in `start'
/Library/Ruby/Gems/1.8/gems/delayed_job-2.1.3/lib/delayed/tasks.rb:9
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:in `call'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:in `execute'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:in `each'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:in `execute'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:597:in `invoke_with_call_chain'
/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/monitor.rb:242:in `synchronize'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:590:in `invoke_with_call_chain'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:583:in `invoke'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2051:in `invoke_task'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `top_level'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `each'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in `top_level'
/Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:in … 我正在尝试使用wxpython为gui编写一个时间表程序,并且正在使用wxpython wiki上的入门教程来加快wxpython的速度,但是当我尝试向wxFrame添加菜单栏时,菜单栏没有显示.任何想法为什么会这样?我使用的是ubuntu 10.10和python 2.7.代码如下:
#! /usr/bin/env python2.7
import wx, os
class MainWindow(wx.Frame):
def __init__(self, parent, title):
wx.Frame.__init__(self, parent, title=title, size=(200,100))
self.control = wx.TextCtrl(self, style=wx.TE_MULTILINE)
self.CreateStatusBar() # A Statusbar in the bottom of the window
# Creating the menubar.
menuBar = wx.MenuBar()
# Setting up the menu.
filemenu= wx.Menu()
# wx.ID_ABOUT and wx.ID_EXIT are standard ids provided by wxWidgets.
menuAbout = filemenu.Append(wx.ID_ABOUT, "&About"," Information about this program")
menuExit = filemenu.Append(wx.ID_EXIT,"E&xit"," Terminate the program")
menuBar.Append(filemenu,"&File") # Adding the "filemenu" to the MenuBar …Run Code Online (Sandbox Code Playgroud) 我想通过密钥合并两个京都内阁 B 树数据库。(京都内阁python api)。结果列表应包含两个输入数据库中任何一个的每个唯一键(及其值)。
以下代码有效,但我认为它丑陋。
left_generator/right_generator 是两个游标对象。如果生成器耗尽, get() 返回 None 尤其奇怪。
def merge_join_kv(left_generator, right_generator):
stop = False
while left_generator.get() or right_generator.get():
try:
comparison = cmp(right_generator.get_key(), left_generator.get_key())
if comparison == 0:
yield left_generator.get_key(), left_generator.get_value()
left_generator.next()
right_generator.next()
elif (comparison < 0) or (not left_generator.get() or not right_generator.get()):
yield right_generator.get_key(), right_generator.get_value()
right_generator.next()
else:
yield left_generator.get_key(), left_generator.get_value()
left_generator.next()
except StopIteration:
if stop:
raise
stop = True
Run Code Online (Sandbox Code Playgroud)
通常:是否有一个函数/库将生成器与 cmp() 合并?
我已经看到最近的代码示例将函数放在变量中,然后像普通函数一样调用函数.
如:
var myFunctionName = function() {
Code Here...
}
myFunctionName();
Run Code Online (Sandbox Code Playgroud)
我相信更先进的场景有很多优点,但我只是好奇.
我正在设计一个允许我模拟我的数据库的设计,以便我可以测试我的观点.我不想阅读关于IOC的完整书籍,因为我现在没有时间.所以,这是我的家常菜.
控制器:
Run Code Online (Sandbox Code Playgroud)public ActionResult Milestone() { var result = SJMServiceFactory.GetService("Milestone"); return View(result); }
厂:
public static class SJMServiceFactory
{
public static DatabaseCollection_Result<T> GetService(string serviceName)
{
switch(serviceName)
{
case("Milestone"): return MileStoneService.GetMilestone();
case ("MilestoneMock"): return MileStoneService.GetMilestone(true);
default : return default(T);
}
}
}
Run Code Online (Sandbox Code Playgroud)
里程碑
public class MileStoneService
{
public MileStoneService()
{
}
public static DatabaseCollection_Result<Milestone> GetMilestone(bool Mock)
{
if (Mock)
{
DatabaseCollection_Result<Milestone> mileStones = new DatabaseCollection_Result<Milestone>();
Milestone milestone1 = new Milestone();
milestone1.Name = "New";
Milestone milestone2 = new Milestone();
milestone2.Name = "Assessment"; …Run Code Online (Sandbox Code Playgroud) 我正在写这个函数.
const int ProgressBarLength = 230;
foreach (TransactionDetail item in list)
{
var itemProgress =
((ProgressBarLength/item.PurchasesRequired) *
Convert.ToInt32(item.TransactionAmount));
item.ProgressBar = itemProgress > ProgressBarLength ? ProgressBarLength : itemProgress;
}
Run Code Online (Sandbox Code Playgroud)
现在TransactionDetail我的循环中有2 秒.
如果item.PurchasesRequired = 500和TransactionAmount = 199.0结果值为0.但是,如果item.PurchasesRequired = 5和TransactionAmount = 94.0它返回有效结果.
我究竟做错了什么?
在之前版本的MATLAB(7.6)中,我曾经得到过OutOfMemoryErrors,我觉得这有点烦人.但是自从我升级到7.11后,出于某种原因它不再抛出错误了.
这意味着当我意外地尝试使变量太大时,MATLAB shell将尝试创建变量并使我的机器停止运行.
我真的很想抛出这些错误,以便我可以优雅地退出或调试我的代码,但我无法在任何地方找到解决方案.
可能有用的细节:我在64位机器上使用OSX 10.5,具有4GB RAM.
在MATLAB 7.6中:
$ rand(50000);
??? Error using ==> rand
Maximum variable size allowed by the program is exceeded.
Run Code Online (Sandbox Code Playgroud)
在MATLAB 7.11中:
$ rand(50000);
(hang)
Run Code Online (Sandbox Code Playgroud) 鉴于此代码
def create
@upgrades = User.update_all(["role = ?","upgraded"], :id => params[:upgrade])
redirect_to admin_upgrades_path, :notice => "Successfully upgraded user."
end
Run Code Online (Sandbox Code Playgroud)
如果保存或不重定向到适当的页面和消息,我如何在该操作中实际验证?
我有这样的文件
(ns boston.core)
Run Code Online (Sandbox Code Playgroud)
(load "boston/core")但是,如果我来自REPL,我*ns*不会改变boston但仍然存在user.为什么是这样?
c# ×2
clojure ×1
delayed-job ×1
eye-tracking ×1
function ×1
generator ×1
javascript ×1
matlab ×1
opencv ×1
python ×1
ruby ×1
variables ×1
wxpython ×1