我在WP7工作.我需要将JSON数组值解析为列表框.有人说,使用Serializer和Deserializer,但我不知道如何使用serilizer和反序列化器将这些值解析为组合框或列表框?
我有一个key.bin文件,其内容类似于:
-12, 110, 93, 14, -48, ...
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服务使用它来解密3DES内容,但我需要通过Ruby加密它.
我已经尝试了大量的场景,如何设置密钥以及如何处理它,但是到目前为止无济于事:
我认为我需要做的事情很简单:
des = OpenSSL::Cipher::Cipher.new('des3')
des.decrypt
des.key = mistery # this step is where i'm having problems at
final = des.update(encrypted) + des.final
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关于我应该用这个键做什么的任何想法?
关键样本:
-62,-53,124,-110,37,-88,-48,31,-57,93,70,-101,44,69,-88,-57,-123,-99,118,-119,110,55,11,14
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数据样本: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=
Run Code Online (Sandbox Code Playgroud) 我试图通过我的Android应用程序的HTTP Post请求访问textalertapp.com.但我收到未知主机错误.任何人都可以帮我解决这个问题.
12-13 01:30:16.058: WARN/System.err(473): java.net.UnknownHostException: textalertapp.com
12-13 01:30:16.088: WARN/System.err(473): at java.net.InetAddress.lookupHostByName(InetAddress.java:513)
12-13 01:30:16.088: WARN/System.err(473): at java.net.InetAddress.getAllByNameImpl(InetAddress.java:278)
12-13 01:30:16.088: WARN/System.err(473): at java.net.InetAddress.getAllByName(InetAddress.java:242)
12-13 01:30:16.088: WARN/System.err(473): at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:136)
12-13 01:30:16.099: WARN/System.err(473): at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164)
12-13 01:30:16.099: WARN/System.err(473): at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119)
12-13 01:30:16.099: WARN/System.err(473): at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:348)
12-13 01:30:16.108: WARN/System.err(473): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555)
12-13 01:30:16.118: WARN/System.err(473): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487)
12-13 01:30:16.118: WARN/System.err(473): at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465)
12-13 01:30:16.118: WARN/System.err(473): at com.textalert.alertCollection.getAlerts(alertCollection.java:46)
12-13 01:30:16.118: WARN/System.err(473): at com.textalert.alertsList$1.run(alertsList.java:81)
12-13 01:30:16.128: WARN/System.err(473): at java.lang.Thread.run(Thread.java:1096)
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代码是
HttpClient client = new DefaultHttpClient();
String postURL …
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// get everything that is either an input or a select
$container.find(':any(input, select)');
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方法的教程?基本上我在我的应用程序中尝试在抛出异常时显示自定义警报对话框.是否有可能做到这一点?我知道在屏幕上显示某些内容有点棘手,如果在UI线程中抛出异常,但我不知道任何解决方法.
我想在此文件中启用所有apt存储库
cat /etc/apt/sources.list
## Note, this file is written by cloud-init on first boot of an instance
## modifications made here will not survive a re-bundle.
## if you wish to make changes you can:
## a.) add 'apt_preserve_sources_list: true' to /etc/cloud/cloud.cfg
## or do the same in user-data
## b.) add sources in /etc/apt/sources.list.d
#
# See http://help.ubuntu.com/community/UpgradeNotes for how to upgrade to
# newer versions of the distribution.
deb http://us-east-1.ec2.archive.ubuntu.com/ubuntu/ maverick main
deb-src http://us-east-1.ec2.archive.ubuntu.com/ubuntu/ maverick main
## Major …
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,None
,0
,并且0.0
将返回False用bool(x)
(在Python 3.X)?
我目前有一个转发器控件,在itemtemplate里面我有一个usercontrol.此用户控件正确呈现,但我尝试将数据项分配给转发器控件中的属性.
<asp:Repeater ID="Repeater1" DataSourceID="EntityDataSource" runat="server">
<ItemTemplate>
<uc1:Request ID="Request1" runat="server" RequestId='<%# Eval("RequestId") %>' />
</ItemTemplate>
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RequestId只是一个Int32.它只是没有分配它.
我可以将eval放在usercontrol之外,只是在itemtemplate中它正确输出正确的id.
如果我删除整个eval并只输入一个数字,那么它可以正常工作.
任何帮助赞赏.
[更新]:问题已解决
我使用的是EntityDataSource,它会自动绑定到转发器.它在屏幕上打印出数据库中的所有信息,没有任何代码隐藏.但是当我把代码放在Repeater1.DataBind()之后; 然后开始工作.
我不知道为什么,但嘿,它已经解决了.它现在成功传递了价值.我想它与页面生命周期有关.